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Nikitich [7]
3 years ago
10

Which of the following describes a Brønsted-Lowry base?

Chemistry
2 answers:
Alina [70]3 years ago
8 0
Anwer: the first option, a hydrogen ion acceptor.

The acid-base model of Bronsted-Lowry is focused on hydrogen ion. An acid is a donor of hydrogen ions and a base is a receptor of hydrogen ions.
jeka57 [31]3 years ago
4 0

\boxed{{\text{A hydrogen ion accept or}}} describes a Bronsted-Lowry base.

Further Explanation:

Different theories have definitions of acids and bases. These theories are as follows:

1. Arrhenius theory: According to this theory, acid produces hydrogen or hydronium ions in a solution, while the base produces hydroxide ions in a solution. HCl, {\text{HN}}{{\text{O}}_3} and  {{\text{H}}_2}{\text{S}}{{\text{O}}_4} are Arrhenius acids while NaOH and KOH are the examples of Arrhenius bases.

2. Bronsted-Lowry theory: This theory defines acid as the proton or hydrogen ion donor and base as the proton or hydrogen ion acceptor. {{\text{H}}_2}{\text{O}} acts as Bronsted acid while {\text{N}}{{\text{H}}_3} is a Bronsted base.

3. Lewis theory: According to this theory, an acid accepts a pair of electrons from electron-rich species while a base donates electrons to electron-deficient species in the reaction. Examples of Lewis acids are {\text{B}}{{\text{F}}_3}, {\text{S}}{{\text{O}}_3} while {{\text{H}}_2}{\text{O}} and ROH are the examples of Lewis base.

A hydrogen ion acceptor

According to Bronsted-Lowry theory, Bronsted-Lowry base is the species that accepts protons or hydrogen ions. So this is incorrect.

An electron pair donor

A compound that donates an electron pair act as Lewis base, not Bronsted-Lowry base. So this is incorrect.

An electron pair acceptor

A compound that accepts an electron pair act as Lewis acid, not Bronsted-Lowry base. So this is incorrect.

A hydrogen ion donor

According to Bronsted-Lowry theory, the species that donates protons or hydrogen ions is known as Bronsted-Lowry acid, not base. So this is incorrect

Learn more:

1. The reason for the acidity of water brainly.com/question/1550328

2. Reason for the acidic and basic nature of amino acid. brainly.com/question/5050077

Answer details:

Grade: High School

Subject: Chemistry

Chapter: Acid, base and salts

Keywords: acid, base, electrons, protons, Arrhenius theory, Lewis theory, Bronsted-Lowry theory, hydrogen, hydronium ion, hydroxide ion, accept, donate, hydrogen ion acceptor, hydrogen ion donor, electron pair donor, electron pair acceptor.

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aliya0001 [1]

Answer:

Velocity

Explanation:

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I think this is the answer, I hope this helps!

3 0
3 years ago
What is the half-life of an isotope that decays to 6.25% of its original activity in 18.9 hours?
inessss [21]
Radioactive material obeys 1st order decay kinetics,
For 1st order reaction, we have 
k = \frac{2.303}{t}Xlog \frac{\text{initial conc.}}{\text{final conc.}}
where, k = rate constant of reaction

Given: Initial conc. 100, Final conc. = 6.25, t = 18.9 hours

∴ k = \frac{2.303}{18.9} X log \frac{100}{6.25} = 0.1467 hours^(-1)

Now, for 1st order reactions: half life = \frac{0.693}{k} =  \frac{0.693}{0.1467} = 4.723 hours.


8 0
3 years ago
Determine the maximum amount of Fe that was produced during the experiment. Explain how you determined this amount.
dsp73

Answer:

5 moles of Fe

Explanation:

The equation of the reaction is;

2 Al(s) + Fe 2O 3(s) --> 2Fe (s) + Al 2O 3 (s)

Now;

1 mole of Fe2O3 require 2 moles of Al

3 moles of Fe2O3 requires 3 × 2/1 = 6 moles of Al

Hence Al is the limiting reactant.

If 2 moles of Al yields 2 moles of Fe

5 moles of Al yields 5 × 2/2 = 5 moles of Fe

5 0
2 years ago
How many atoms of iodine are needed to react with one atom of magnesium?
kotegsom [21]

Answer:

uh

Explanation:

4 0
3 years ago
a 32 gram radioactive sample has a half-life of 2 days how much of the original sample remains after 6 days
bixtya [17]
First, we will get the "n", the number of half lives, it is the elapsed time over the half life. In the problem, the time is measured in days, so we have 

6/2 = 3 

to get the ending amount of radioactive sample, we have

32g x (1/2)³ = 4 grams of radioactive sample ⇒ the amount left after 6 days


3 0
3 years ago
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