Answer:
NO
Step-by-step explanation:
Look at the figure attached below, we know that the area of the cone is the sum of area of circle part and cone part of the figure.
to find the surface area of the cone, first measure the radius of the base and find the area of the circle part by formula 
. Then measure the side (slant height) length of the cone part and find the area of the cone part by the formula 
.
Now the surface area of the cone is circumference of the circle plus area of the cone part.
i.e. 
From the above discussion we concluded that surface area of the cone does not depend only on the circumference of the base but also we need side length of the cone part as well thus <em>all cones with a base circumference of 8 inches will </em><em>not </em><em>have the same surface area.</em>
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First, "boxes of two sizes" means we can assign variables: Let x = number of large boxes y = number of small boxes "There are 115 boxes in all" means x + y = 115 [eq1] Now, the pounds for each kind of box is: (pounds per box)*(number of boxes) So, pounds for large boxes + pounds for small boxes = 4125 pounds "the truck is carrying a total of 4125 pounds in boxes" (50)*(x) + (25)*(y) = 4125 [eq2] It is important to find two equations so we can solve for two variables. Solve for one of the variables in eq1 then replace (substitute) the expression for that variable in eq2. Let's solve for x: x = 115 - y [from eq1] 50(115-y) + 25y = 4125 [from eq2] 5750 - 50y + 25y = 4125 [distribute] 5750 - 25y = 4125 -25y = -1625 y = 65 [divide both sides by (-25)] There are 65 small boxes. Put that value into either equation (now, which is easier?) to solve for x: x = 115 - y x = 115 - 65 x = 50 There are 50 large boxes.
Answer:
Step-by-step explanation:
If BOTH equations are in slope-intercept form then the-graphing-? method would be best, but the-substitution-? method would also be effective since both y's are already by itself.
If ONE of the equations is solved for x or y and the other equation is not, then the-substitution-? method is best.
If BOTH equations are lined up in standard form & the coefficients of x or y are opposites then the BEST method is definitely the-elimination--? method.
If BOTH equations are lined up in standard form the elimination method would be best. But if the coefficient of x or y is 1, then the-substitution--? method is also effective.
Answer:
31
Step-by-step explanation:
