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Charra [1.4K]
3 years ago
13

Which is the closest antonym for the word prone?​

Chemistry
1 answer:
tigry1 [53]3 years ago
3 0

Answer:

vertical, upright, erect, disinclined.

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A student finds a piece of metal that she thinks is aluminum. She finds the volume to be 245 cm^3 and the mass to be 612 grams.
natta225 [31]

Answer:

Density = 2.5 g/cm³ , The metal is aluminium.

Explanation:

Density is defined as the ratio of the mass and the volume

Thus,

Density=\frac {Mass}{Volume}

Given that:

Mass  = 612 grams

Volume = 245 cm³

Thus, Density is:

Density=\frac {612}{245}\ g/cm^3

<u>Density = 2.5 g/cm³</u>

Metals are shiny with high density.

<u><em>The density of aluminium falls is approx 2.6 g/cm³ and not other metal's density falls in this range. </em></u>

<u><em>The metal is aluminium.</em></u>

<u><em></em></u>

3 0
4 years ago
Convert 2.60 meters per second to mph
Gnoma [55]
5.81603 miles per hour
3 0
4 years ago
A double replacement reaction occurs when aqueous potassium iodide and aqueous mercury (I) nitrate are mixed. What is the correc
pashok25 [27]
The answer should be 2KI(aq)+Hg(NO3)2(aq) = 2KNO3(aq) + HgI2(s). This is a double replacement reaction, the valence of elements will not change. The HgI2 is not soluble in water.
4 0
3 years ago
The chemical formula for strontium sulfite is SrSO3.<br><br><br> TRUE<br><br><br> FALSE
VLD [36.1K]
Valency is the number of electrons lost or gained by an atom to attain an stable configuration. Valency is important when writing the formula of chemical compounds in chemistry. Strontium has a valency of  2 while sulfite ion (radicle) has a valency of 2. Therefore, the chemical formula of strontium sulfite is written as SrSO3.
3 0
3 years ago
The Ksp of CaF2 is 4.0 x 10-11. What is the solubility of CaF2 in 0.10 M Ca(NO3)2? Give your answer using scientific notation an
Ilya [14]

Answer:

1.0\times 10^{-5} M is the solubility of CaF_2 in 0.10 M Ca(NO_3)_2.

Explanation:

Concentration of calcium nitrate = [Ca(NO_3)_2]=0.10 M

Ca(NO_3)_2\rightarrow Ca^{2+}+2NO_3^{-}

[Ca(NO_3)_2]=0.10 M=[Ca^{2+}]

Solubility product of the calcium fluoride = K_{sp}=4.0\times 10^{-11}

Solubility of calcium fluoride in calcium nitrate solution :

CaF_2\rightleftharpoons Ca^{2+}+2F^-

            (0.10+S)   (2S)

The expression of solubility is given by :

K_{sp}=[Ca^{2+}][F^-]^2

4.0\times 10^{-11}=(S+0.10)(2S)^2

Solving for S:

S=1.0\times 10^{-5} M

1.0\times 10^{-5} M is the solubility of CaF_2 in 0.10 M Ca(NO_3)_2.

3 0
3 years ago
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