Answer:
Fe2(SO4)3 + 3BaCl2 → 2FeCl3 + 3BaSO4
Answer:
The stronger conjugate base will be the weaker acid; i.e., the acid with the smaller Ka-value.
Explanation:
Given conjugate base CN⁻ => weak acid => HCN => Ka =4.9 x 10⁻¹⁰
Given conjugate base OCN⁻ => weak acid=> HOCN => Ka = 3.5 x 10⁻⁴
Ka(HCN) << Ka(HOCN) => CN⁻ is a much stronger conjugate base than OCN⁻
Refer to the diagram shown below.
The second axis is at the centroid of the rod.
The length of the rod is L = 100 cm = 1 m
The first axis is located at 20 cm = 0.2 m from the centroid.
Let m = the mass of the rod.
The moment of inertia about the centroid (the 2nd axis) is

According to the parallel axis theorem, the moment of inertia about the first axis is

The ratio of the moment of inertia through the 2nd axis (centroid) to that through the 1st axis is

Answer: 0.676
We can solve this problem by using Henry's law.
Henry's law states that the amount of dissolved gas is proportional to its partial pressure.

C is <span>the solubility of a gas.
</span><span>k is Henry's law constant.
</span><span>P is the partial pressure of the gas.
</span>We can calculate the constant from the first piece of information and then use Henry's law to calculate solubility in open drink.
0.12=4k
k=0.03
Now we can calculate the solubility in open drink.


Now we need to convert it to g/L. One mol of CO2 is 44.01<span>g.
</span>The final answer is: