The following are bronsted- lowery acids. Determine what will form when each donates a proton. HI, H2O, NH4+, HNO3

1 answer:

6 0

1) Chemical reaction: HI(aq) → H⁺(aq) + I⁻(aq).
It gives an iodide anion.
2) Chemical reaction: H₂O → H⁺(aq) + OH⁻(aq).
It gives a hydroxide anion.
3) Chemical reaction: NH₄⁺(aq) → H⁺(aq) + NH₃(aq).
It gives ammonia.
4) Chemical reaction: HNO₃(aq) → H⁺(aq) + NO₃⁻(aq).
It gives nitrate anion.

You might be interested in

Does a physical change form a new substance

beks73 [17]

Answer:

No. No new substance is formed during Physical change.

4 0

3 years ago

Calculate the Kc for the following reaction if an initial reaction mixture of 0.500 mole of CO and 1.500 mole of H2 in a 5.00 li

Temka [501]

Answer:

can you be more clear with your question :

7 0

2 years ago

Fluorine (F) has seven electrons in its outermost shell. Fluorine _____.

kow [346]

Fluorine is a nonmetal and as such it would need to take in or obtain an electron from a metal to have a stable octet, or full number of 8 electrons in its valence shell. Thus due to the indifference of electrons and protons it becomes an anion, a negatively charged ion.

7 0

4 years ago

Read 2 more answers

Suppose a 0.025M aqueous solution of sulfuric acid (H2SO4) is prepared. Calculate the equilibrium molarity of SO4−2. You'll find

FromTheMoon [43]

Answer: The concentration of $SO_4^{2-}$ at equilibrium is 0.00608 M

Explanation:

As, sulfuric acid is a strong acid. So, its first dissociation will easily be done as the first dissociation constant is higher than the second dissociation constant.

In the second dissociation, the ions will remain in equilibrium.

We are given:

Concentration of sulfuric acid = 0.025 M

Equation for the first dissociation of sulfuric acid:

$H_2SO_4(aq.)\rightarrow H^+(aq.)+HSO_4^-(aq.)$