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3 years ago

The following are bronsted- lowery acids. Determine what will form when each donates a proton. HI, H2O, NH4+, HNO3

1 answer:

6 0

1) Chemical reaction: HI(aq) → H⁺(aq) + I⁻(aq).
It gives an iodide anion.
2) Chemical reaction: H₂O → H⁺(aq) + OH⁻(aq).
It gives a hydroxide anion.
3) Chemical reaction: NH₄⁺(aq) → H⁺(aq) + NH₃(aq).
It gives ammonia.
4) Chemical reaction: HNO₃(aq) → H⁺(aq) + NO₃⁻(aq).
It gives nitrate anion.

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Hydrochloric acid and sodium hydroxide are mixed together to form salt and water. During the reaction, the temperature of the so

sammy [17]

The best answer among the choices is option D. New substances are being formed will best explain that this process is a chemical change. Although, it cannot be seen directly we knew that an acid and base will undergo neutralization reaction forming a salt and water. The heat given off by the reaction can be a parameter however it does not only happens for reactions. It can also happen when dissolving substances.

6 0

3 years ago

Which type of surface would best reflect light?

marishachu [46]

Answer:

Honestly I would guess D

Explanation:

sorry if im wrong

8 0

3 years ago

Read 2 more answers

At 293 K, methanol has a vapor pressure of 97.7 Torr and ethanol has a vapor pressure of 44.6 Torr. What would be the vapor pres

Bad White [126]

Answer: The vapor pressure of a mixture of 80 g of ethanol and 97 g of methanol at 293 K is 78.3 torr.

Explanation:

According to Raoult's law, the vapor pressure of a component at a given temperature is equal to the mole fraction of that component multiplied by the vapor pressure of that component in the pure state.

$p_1=x_1p_1^0$ and $p_2=x_2P_2^0$

where, x = mole fraction in solution

$p^0$ = pressure in the pure state

According to Dalton's law, the total pressure is the sum of individual pressures.

$p_{total}=p_1+p_2$ $p_{total}=x_Ap_A^0+x_BP_B^0$

moles of ethanol= $\frac{\text{Given mass}}{\text {Molar mass}}=\frac{80g}{46g/mol}=1.7moles$

moles of methanol= $\frac{\text{Given mass}}{\text {Molar mass}}=\frac{97g}{32g/mol}=3.0moles$

Total moles = moles of ethanol + moles of methanol = 1.7 +3.0 = 4.7

$x_{ethanol}=\frac{1.7}{4.7}=0.36,$

$x_{methanol}=1-x_{ethanol}=1-0.36=0.64$

$p_{ethanol}^0=44.6torr$

$p_{methanol}^0=97.7torr$

$p_{total}=0.36\times 44.6+0.64\times 97.7=78.3torr$

Thus the vapor pressure of a mixture of 80 g of ethanol and 97 g of methanol at 293 K is 78.3 torr.

8 0

4 years ago

Calculate your experimentally determined percent mass of water in Manganese(II) sulfate monohydrate. Report your result to 2 or

antoniya [11.8K]

Answer:

10.6%

Explanation:

The determined percent mass of water can be calculated from the formula of the hydrate by

dividing the mass of water in one mole of the hydrate by the molar mass of the hydrate and

multiplying this fraction by 100.

Manganese(ii) sulphate monohydrate is MnSO4 . H2O

1. Calculate the formula mass. When determining the formula mass for a hydrate, the waters of

hydration must be included.

1 Manganes 52.94 g = 63.55 g

1 Sulphur 32.07 g =

32.07 g 2 Hydrogen is = 2.02 g

4 Oygen =

64.00 g 1 Oxygen 16.00 = 16.00 g

151.01 g/mol 18.02 g/mol

Formula Mass = 151.01 + (18.02) = 169.03 g/mol

2. Divide the mass of water in one mole of the hydrate by the molar mass of the hydrate and

multiply this fraction by 100.

Percent hydration = (18.02 g /169.03 g) x (100) = 10.6%

The final result is 10.6% after the two steps calculations

4 0

3 years ago

How many valence electrons does boron need to be stable?

MAVERICK [17]

Because Boron has 3 valence electrons it will need to lose valence electrons to have a (in this case) a empty valence shell. This means that it will lose 3 valence electrons to become stable

8 0

4 years ago