What type of bonding is found in the compound of2?

What is the empirical formula for a compound that is 29.44\% calcium, 23.55% sulfur, and 47.01% oxygen? This compound is a commo

PSYCHO15rus [73]

Answer:

Empirical formula is CaSO₄.

Explanation:

Given data:

Percentage of calcium =29.44%

Percentage of sulfur = 23.55%

Percentage of oxygen = 47.01%

Empirical formula = ?

Solution:

Number of gram atoms of Ca = 29.44 / 40 = 0.74

Number of gram atoms of S = 23.55 / 32 = 0.74

Number of gram atoms of O = 47.01 / 16 = 3

Atomic ratio:

Ca : S : O

0.74/0.74 : 0.74/0.74 : 3/0.74

1 : 1 : 4

Ca : S : O = 1 : 1 : 4

Empirical formula is CaSO₄.

3 0

2 years ago

Suppose the price of gasoline increases 10% and quantity of gasoline demanded in Orlando drops 5% per day. Demand for gasoline i

grin007 [14]

Answer:

The correct answer is;

Demand for gasoline in Orlando is price inelastic.

Explanation:

The elasticity is the degree of response to a change in price or quantity supplied to the the quantity demanded. An elastic demand responds positively to change in price, while an inelastic demand means that when there is a price increase, the quantity demanded remains the same and where there is a drop in price the quantity demanded remains constant.

If a small change in price results in a large change in demand then the good is said to be price elastic

In the question the price increases by 10% while the quantity demanded drops 5 % daily. Therefore it is price inelastic

5 0

3 years ago

Calculate the net change in enthalpy for the formation of one mole of nitric acid from nitrogen, hydrogen and oxygen from these

deff fn [24]

The formation of nitric acid from nitrogen, hydrogen, and oxygen can be written as,

N₂ + H₂ + 3O₂ --> 2HNO₃

The net enthalpy of formation of nitric acid is calculated by,
Hrxn = Hproduct - Hreactant

Since all the reactants are in their elemental forms, the simplified equation would be,

Hrxn = Hproduct

Substituting,

Hrxn = (-186.81 kJ/mol)(2 mols)

Answer: -372.42 kJ

7 0

3 years ago

Which of the following best describes an advantage of cloning? Can prevent genetic diseases Can increase genetic diversity Helps

s344n2d4d5 [400]

The statement that best describes an advantage of cloning is that it can prevent genetic diseases. DNA cloning is a term used in recombinant DNA technology happens when a DNA strand belonging to one organism is transmitted into a particular type of genetic element having the capacity to self replicate. DNA cloning was developed to offer solutions related to healthcare and medical issues. Illnesses occur mostly because our body fails to produce essential proteins in ample amount is needed, these problems and other inherited problems may be solved using DNA cloning.

5 0

3 years ago

When 50.0 mL of 1.27 M of HCl(aq) is combined with 50.0 mL of 1.32 M of NaOH(aq) in a coffee-cup calorimeter, the temperature of

sergij07 [2.7K]

Answer:

-55.9kJ/mol is the change in enthalpy of the reaction

Explanation:

In the reaction:

HCl(aq) + NaOH(aq) → H₂O(l) + NaCl

Some heat is released per mole of reaction.

To know how many moles reacts we need to find limiting reactant:

Moles HCl = 0.050L ₓ (1.27mol / L) = 0.0635 moles HCl

Moles NaOH = 0.050L ₓ (1.32mol / L) = 0.066 moles NaOH

As there are more moles of NaOH than moles of HCl, HCl is limiting reactant and moles of reaction are moles of limiting reactant, 0.0635 moles

Using the coffee-cup calorimeter equation we can find how many heat was released thus:

Q = C×m×ΔT

Where Q is heat released, C is specific heat of the solution (4.18J/g°C), m is mass of solution (100g because there are 100mL of solution -50.0mL of HCl and 50.0mL of NaOH- and density is 1g/mL) and ΔT is change in temperature (8.49°C)

Replacing:

Q = 4.18J/g°C×100g×8.49°C

Q = 3548.8J of heat are released in the reaction

Now, change in enthalpy, ΔH, is equal to change in heat (As is released heat ΔH < 0) per mole of reaction, that is:

ΔH = Heat / mol of reaction

ΔH = -3548.8J / 0.0635 moles of reaction

Negative because is released heat.

ΔH = -55887J / mol

ΔH =

<h3>-55.9kJ/mol is the change in enthalpy of the reaction</h3>

3 0

2 years ago