Twenty-one thousand four hundred
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Given a defined function
f(x), we can evaluate the function at any constant by replacing every x
with that constant.So if f(x)=3x+5x, then f(a+2)=3(a+2)\+5a+2
Answer:
the arrow would start at -2 1/2 and end at 1 1/2
5)
= - i - 2 - 3i
= - 4i - 2
= - 2 (2i + 1)
7)
= - 4 [(2 -2i - i (8 - 4i)]
= - 4 (2 - 2i - 8i + 4i^2)
= - 4 (4i^2 - 10i + 2)
= (- 4) (2) (2i^2 - 5i + 1)
= - 8 (2i^2 - 5i + 1)
9)
= p^2 - 4p - 4p + 16
= p (p - 4) - 4 (p - 4)
= (p - 4) (p - 4)
= (p - 4) ^2
11)
= p^2 - 8p - 8p + 64
= b (b - 8) - 8 (b - 8)
= (b - 8) (b - 8)
= (b - 8)^2
Y=Ix+1I-3
the absolute value of( x+1) minus 3
