HCl is <span>limiting reactant, Mg in excess therefore:
</span><span>number of moles HCl:
75.0 mL in liters: 75.0 / 1000 => 0.075 L
Molarity HCl = 1.0 M
n = M x V
n = 1.0 x 0.075
n = 0.075 moles of HCl
</span>Mg(s) + 2 HCl (aq) = H2 (g) + MgCl2 (aq)
<span>2 moles HCl -------------------- 1 mole H2
</span><span>0.075 moles of HCl ------------ ( moles H2)
</span>
moles H2 = 0.075 x 1 / 2
moles H2 = 0.075 / 2
= 0.0375 moles of H2
hope this helps!
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Answer:
67.824
Explanation: You want to use the combined gas law equation (P1*V1)/(n1*T1)=(P2*V2)/(n2*T2). So first cross out what remains constant, so volume(V) and I assume moles (since it was not mentioned as a change). Then you can solve algebraically for the answer!
Hope this helped!
A toothbrush that has toothpaste in the middle so it comes preloaded. That way it is cleaner and uses more product than normal
Answer:
1.09 moles of NaOH
Explanation:
First of all, to calculate moles, you need to find the molar mass of NaOH.
Let us first find the molar mass of NaOH then.
Na = 23.0 amu
O = 16.0
H = 1.0
They are 1 nitrogen atom, 1 oxygen atom, and one hydrogen atom.
So do this.
23.0(1) + 16.0(1) + 1.0(1) = 40 g/mol.
Now use dimensional analysis to show your work
43.5 g of NaOH * 1 mol of NaOH / 40 g/mol of NaOH
The grams cancel out.
43.5 / 40.0 = 1.0875
Use sig figs and round the answer to the nearest hundredths place.
1.0875 = 1.09
So the final answer is 1.09 moles of NaOH
Hope it helped!
Answer:
Native Elements; Metallic Elements
Explanation:
