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liubo4ka [24]
3 years ago
11

Given tan∅=4/3 and π<∅<(3π)/2; find cos2∅

Mathematics
1 answer:
Snezhnost [94]3 years ago
3 0

Answer:

cos(2\theta)=-\frac{7}{25}

Step-by-step explanation:

we are given

tan(\theta)=\frac{4}{3}

Firstly, we will draw triangle

Since, angle lies in third quadrant

so,

sin(\theta)=-\frac{4}{5}

cos(\theta)=-\frac{3}{5}

now, we can sue formula

cos(2\theta)=cos^2(\theta)-sin^2(\theta)

now, we can plug values

cos(2\theta)=(-\frac{3}{5})^2-(-\frac{4}{5})^2

we can simplify it

cos(2\theta)=-\frac{7}{25}

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Given the graph of a scatterplot and a trend line, explain how you would find the equation of the trend line.
SpyIntel [72]

To find the equation of a trend line, It is important to find the X axis and Y axis, Once x axis and y axis  is found if there is an association between x axis and y axis, We use linear equation to produce the trend line. Linear regression or algorithm called as OLS (Ordinary least square). Y= mx +c

y = dependent variable, x = independent variable , constant = c , m  = y2-y1/x2-x1.

Step-by-step explanation:

  • Scatter plot is to find association of two different variable.
  • Trend line is the equation between xaxis and y axis.
  • Prediction is best way to form equation.
  • Linear regression y=mx +c
  • Equation helps in predictive modelling between next best form.
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5 0
3 years ago
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PLEASE HELP ASAP!! URGENT!!
Black_prince [1.1K]
A= 9
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4 0
4 years ago
PLease answer!!! 30 points!!!
Agata [3.3K]

Answer:

a

Step-by-step explanation:

They make a right angle. A right angle adds up to 90.

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4 years ago
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In a volleyball game, a player on one team spikes the ball over the net when the ball is 10 feet above the court. The spike driv
Fynjy0 [20]

Answer:

4.75 seconds

Step-by-step explanation:

Initial height of the ball from the ground = 10 feet

Upward initial velocity given = 55 feet per second

Value of g ( acceleration due to gravity) = 32.2 feet per s²

Motion of the ball:

The ball first goes vertically upwards, gravity decelerates the body and it momentarily comes to rest at a point in its upward trajectory, which is the point of maximum height. From this point, to the ground, the ball behaves as a freely dropped body.

Till the ball reaches its maximum height:

u = + 55

v = 0 ( final velocity is zero)

a = - 32.2 (since it is deceleration)

we know that <em>v = u + at </em>

⇒    0 = 55 - 32.2t

⇒  t = 1.7 s

Also , we have <em>s = ut + (1/2)at²</em>

Here, s is the maximum height from the point where ball is thrown

So,     s = 55(1.7) - (0.5)(32.2)(1.7)(1.7)

⇒ s = 140 feet

So at a height of 140 feet + 10 feet (initial height) = 150 feet, the ball acts as a freely dropped body.

Here,      u = 0

               a = +32.2

               s= 150

<em>s = ut + (1/2)at²</em>

⇒  150 = 0.5 ( 32.2) (t²)

⇒  t² = 300/32.2 = 9.31

⇒ t = 3.05 sec

So total time = 1.7 + 3.05 = 4.75 seconds

8 0
4 years ago
Please help me on this homework assignment, I'm not sure I got this right.
Burka [1]

Answer:

1,875$ in intrest

Step-by-step explanation:

10000x.0375x5=1875

7 0
3 years ago
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