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spayn [35]
3 years ago
15

Number 1 and 2 please (25 points)

Mathematics
1 answer:
Elenna [48]3 years ago
8 0

Answers:

1) (3x+2)+(4-5x)=-2x+6

(3+2i)+(4-5i)=7-3i

2) (1-3x)(2+x)=-3x^{2}-5x+2

(1-3i)+(2+i)=5-5i

Step-by-step explanation:

In mathematics there are rules related to complex numbers, specifically in the case of addition and multiplication:

<u>Addition: </u>

If we have two complex numbers written in their binomial form, the sum of both will be a complex number whose real part is the sum of the real parts and whose imaginary part is the sum of the imaginary parts (similarly as the sum of two binomials).

For example,  the addition of these two binomials is:

(3x+2)+(4-5x)=3x-5x+2+4=-2x+6

Similarly, the addition of two complex numbers is:

(3+2i)+(4-5i)=3+4+2i-5i=7-3i Here the complex part is the number with the i

<u>Multiplication: </u>

If we have two complex numbers written in their binomial form, the multiplication of both will be the same as the multiplication (product) of two binomials, taking into account that i^{2}=-1.

For example,  the multiplication of these two binomials is:

(1-3x)(2+x)=2+x-6x-3x^{2}=-3x^{2}-5x+2

Similarly, the multiplication of two complex numbers is:

(1-3i)+(2+i)=2+i-6i-3i^{2}=2-5i-3(-1)=5-5i

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(4x+ 1) - 3i = 2+ (3y + 5)i
Vesna [10]

(4x+1)-3i= 2 +(3y+5)i

3 0
3 years ago
Maths easy class 8 whoever gets it I will give u brainlist​
asambeis [7]

Answer:

424 cm²

Step-by-step explanation:

The figure is composed of a square and a trapezium on top

A of square = 18² = 324 cm²

A of trapezium = \frac{1}{2} h (b₁ + b₂ )

where h is the perpendicular height and b₁, b₂ the parallel bases

Here h = 8, b₁ = 18 and b₂ = 7 , then

A = 0.5 × 8 × (18 + 7) = 4 × 25 = 100 cm²

Area of hexagonal park = 324 + 100 = 424 cm²

8 0
2 years ago
How do you solve this equation?
Travka [436]
Exponentail thingies

easy, look at all them them, see that they have 5 in common?
rremember how esay it was to factor
ax^2+bx+c=0

now we have
5^(2x)-6(5^x)+5=0
remember that 5^(2x)=(5^2)^x or (5^x)^2
in other words, we can rewrite it as
1(5^x)^2-6(5^x)+5=0
if yo want, replace 5^x with a and factor
1a^2-6a+5=0
(a-1)(a-5)=0
a=5^x
(5^x-1)(5^x-5)=0
set each to zero

5^x-1=0
5^x=1
take the log₅ of both sides
x=log₅1


5^x-4=0
5^x=4
take the log₅ of both sides
x=log₅4

x=log₅1 and/or log₅4







second quesiton

same thing

1(2^x)-10(2^x)+16=0
factor
(2^x-8)(2^x-2)=0
set each to zero

2^x-8=9
2^x=8
x=3

2^x-2=0
2^x=2
x=1

x=3 or 1







first one
x=log₅1 and/or log₅4
second one
x=1 and/or 3


7 0
3 years ago
10=Z+6 can u please solve it in evaluate the expression
Eva8 [605]

Answer: z=4

Step-by-step explanation:

Subtract 6 on both sides and 10-6=4 and then plug 4 into z and the equation is true

8 0
3 years ago
Read 2 more answers
What value does each equation need to be multiplied by in order to eliminate the y terms equation 1 6x-5y=-4 equation 2 4x+2y=28
Alex777 [14]
In order to eliminate the y term, you need to find what y is equal to in the equation.
1. 6x-5y=-4
-5y=-4-6x
Y=6/5x+4/5
You then sub in 6/5x+4/5 in for y in the equation
2. 4x+2y=28
2y=-4x+28
Y=-2x+14
Hope this helps!
5 0
3 years ago
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