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vichka [17]
3 years ago
14

Which of the following was originally a tenet of Dalton's atomic theory, but had to be revised about a century ago?

Chemistry
1 answer:
enot [183]3 years ago
6 0

Answer:

Atoms of different elements can combine with one another in simple whole number ratios

You might be interested in
How much heat is needed to melt 10.0 grams of ice at -10°C until it is water at 10°C?
zhannawk [14.2K]

The heat needed to melt 10.0 grams of ice at -10°C until it is water at 10°C is 3,969.5 J. (approx= 3963J).

<h3>What is Sensible heat? </h3><h3 />

Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state.

Q= c×m×∆T

<h3>What is Latent heat? </h3><h3 />

Latent heat is defined as the energy required by a quantity of substance to change state.

When this change consists of changing from a solid to a liquid phase, it is called heat of fusion and when the change occurs from a liquid to a gaseous state, it is called heat of vaporization.

In this case, the heat Q that is necessary to provide for a mass m of a certain substance to change phase is equal to

Q= m×L

Where,

L is the latent heat

<h3>-10°C to 0 °C</h3><h3 />

C= specific heat capacity of ice= 2.108 J/gK

M= 10 g

ΔT= T(final)– T(initial) = 0 °C – (-10 °C)= 10 °C= 10 K

Sensitive heat Q(1) = 2.108×10×10

= 210.8J

<h3>Heat needed to melt ice</h3><h3 />

The specific heat of melting of ice is 334 J/g, the heat needed to melt 10 grams of ice is

Q(2) = 10× 334

= 3340J

<h3>0°C to 10 °C</h3><h3 />

C= specific heat capacity of liquid water is 4.187 J/gK

M= 10 g

ΔT= T(final) – T(initial) = 10 °C – 0 °C= 10 °C= 10 K because being a temperature difference, the difference is the same in °C and K.

Q(3) = 4.187×10×10

= 418.7 J.

Total heat required= Q1 + Q2 + Q3

Total heat required= 210.8 J + 3,340 J + 418.7 J

= 3969.5J

Thus, the heat needed to melt 10 gram of ice from temperature-10°C to 10°C is 3969.5. Therefore, option B is correct option.

learn more about heat :

brainly.com/question/16818736

#SPJ1

8 0
2 years ago
If gas is initially at 350L and 500k then changes to 295K what is the new volume
Dimas [21]
<h2>Hello!</h2>

The answer is:

The new volume is equal to 206.5 L.

<h2>Why?</h2>

To solve this problem, we need to assume that the pressure is constant, and use the Charle's Law equation, so, solving we have:

\frac{V_1}{T_1}=\frac{V_2}{T_2}

We are given:

V_1=350L\\T_1=500K\\T_2=295K

Then, using the Charle's Law equation, we have:

\frac{350L}{500K}=\frac{V_2}{295K}

\frac{350L}{500K}=\frac{V_2}{295K}\\\\V_2=\frac{350L}{500K}*295K=206.5L

Hence, we have that the new volume is equal to 206.5 L.

Have a nice day!

5 0
2 years ago
Why can't methanol, CH3OH, be used as a solvent for sodium amide, NaNH2? Sodium amide is nonpolar and methanol is polar. Sodium
Elodia [21]

Answer: sodium amide undergoes an acid -base reaction

Explanation:

sodium amide is a ionic compound and basically exists as sodium cation and amide anion. Amide anion is highly basic in nature and hence as soon as  there is amide anion generated in the solution , Due to its very pronounced acidity it very quickly abstracts the slightly acidic proton available on methanol.

This leads to formation of ammonia and sodium methoxide.

Hence sodium amide reacts with methanol and abstracts its only acidic proton and form ammonia and sodium Methoxide.

Hence the 3rd statement is a corrects statement.

So we cannot use methanol for sodium amide because sodium amide itself would react with methanol and the inherent molecular natur of sodium amide would then change.

The 1st and 2nd statements both are incorrect because both the compounds methanol as well as sodium amide have dipole moments and hence are polar molecules.

The 4th statement is also incorrect as both the molecules have dipole moment and hence there would be ion-dipole forces operating between them.

The following reaction occurs:

NaNH₂+CH₃OH→NH₃+CH₃ONa

4 0
2 years ago
How many grams of a 26.9% sugar solution contain 49.0 g of sugar?
Ronch [10]

Answer:

182.156g

Explanation:

grams = 49/.269 = 182.156g needed

6 0
2 years ago
A chemical reaction is shown below:
BabaBlast [244]

Answer:

Mass = 8.46 g

Explanation:

Given data:

Mass of water produced = ?

Mass of glucose = 20 g

Mass of oxygen = 15 g

Solution:

Chemical equation:

C₆H₁₂O₆ + 6O₂     →   6H₂O + 6CO₂

Number of moles of glucose:

Number of moles = mass/molar mass

Number of moles = 20 g/ 180.16 g/mol

Number of moles = 0.11 mol

Number of moles of oxygen:

Number of moles = mass/molar mass

Number of moles = 15 g/ 32 g/mol

Number of moles = 0.47 mol

now we will compare the moles of water with oxygen and glucose.

               C₆H₁₂O₆           :            H₂O

                   1                   :              6

                 0.11                :           6/1×0.11 = 0.66

                   O₂               :            H₂O

                   6                   :              6

                 0.47                :           0.47

Less number of moles of water are produced by oxygen thus it will limit the yield of water and act as limiting reactant.

Mass of water produced:

Mass = number of moles × molar mass

Mass = 0.47 mol  ×18 g/mol

Mass = 8.46 g

8 0
2 years ago
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