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ipn [44]
2 years ago
10

The net ionic equation for the precipitation reaction that occurs when aqueous solutions of silver(i) nitrate and chromium(iii)

chloride are combined.
Chemistry
1 answer:
eduard2 years ago
3 0

The net ionic equation formed is

       Ag^+(aq)+Cl^−(aq)→AgCl(s)

Chromium(III) nitrate and silver(I) chloride are the products of the balanced molecular equation for the reaction between chromium(III) chloride and silver(I) nitrate. An (s) next to the chemical formula for silver(I) chloride designates it as an insoluble salt.

      CrCl3(aq)+3AgNO3(aq)→Cr(NO3)3(aq)+3AgCl(s)

Silver and the chloride ions are the two ions that must interact to create silver(I) chloride. By designating ions as the reactants and silver(I) chloride as the product, the net ionic equation is formed.

      Ag^+(aq)+Cl^−(aq)→AgCl(s)

Ionic Equation:

In general, anions and cations react to generate a compound in a dissolved media, which is known as an ionic reaction. Water-insoluble salts are created when the ions of water-soluble salts interact with one another in an aqueous media.

To learn more about Ionic equaion click the given link

brainly.com/question/19705645

#SPJ4

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Consider the nuclear equation below. Superscript 235 subscript 92 upper U right arrow superscript 4 subscript 2 upper H e. What
coldgirl [10]

Answer:

\rm_{90}^{231}\text{Th}

Explanation:

The unbalanced nuclear equation is

\rm _{92}^{235}\text{U} \longrightarrow \,  _{2}^{4}\text{He} + X

Let's write X as a nuclear symbol.

\rm _{92}^{235}\text{U} \longrightarrow \,  _{2}^{4}\text{He} + _{Z}^{A}\text{X}

The main point to remember in balancing nuclear equations is that the sums of the superscripts and of the subscripts must be the same on each side of the reaction arrow.

Then

235 = 4 + A , so A = 235 - 4 = 231, and

 92 = 2 + Z , so  Z =   92 - 2 =  90

And your nuclear equation becomes

\rm _{92}^{235}\text{U} \longrightarrow \,  _{2}^{4}\text{He} +\, _{90}^{231}\text{X}

Element 90 is thorium, so  

\rm X = _{90}^{231}\text{Th}

7 0
3 years ago
Three 6−l flasks, fixed with pressure gauges and small valves, each contain 6 g of gas at 276 k. flask a contains ch4, flask b c
Margaret [11]

First, please check the missing part in your question in the attachment.

a) So first, the Rank of pressure:

according to this formula PV = nRT and when n = m/Mw

PV = m/Mw * R*T

when we have the same mass m and the same V volume so P will proportional with the mole weight M as when the M is smaller the pressure will be greater 

when Mw of H2(A) = 2 g / Mw of He (B) = 4 g and Mw of CH4(C) = 16 g

∴ Pressure :

 (A) > (B) > (c)

B) The rank of average molecular kinetic energy:

when K = 3/2 KB T

when K is the average kinetic energy per molecule of gas 

and KB is Boltzmann's constant

and T is the temperature (K)

So from this equation, we can know that K only depends on T value, and when we have the T constant here for A, B, and C So the rank of K will be like the following:

∴ A = B = C

C) the rank of diffusion rate after the valve is opened:

according to this formula:

R2/R1 = √M1/M2

from this equation, we can see that diffusion is proportional to the reciprocal of the molecular mass M so,

when Mw H2 (A) = 2 g & Mw He(B) = 4 g & CH4 (C) = 16 g

∴ the rank of diffusion:

A > B > C

D) The rank of the Total kinetic energy of the molecules:

when we have the Mw different so it will make the no.of molecules differs as when the Mw is low the no.of molecules will be hight, and when the average molecular kinetic energy equals. so the total kinetic energy will depend on no. of molecules 

∵ Mw A < Mw B < Mw C 

∴no .of molecules of A > B >C

∴ the rank of total kinetic energy is:

A > B > C

e) the rank of density:

when ρ = m/ v 

and m is the mass & v is the volume and we have both is the same for A, B, and C

so the density also will be the same, ∴ the rank of the density is:

A = B = C

F) the rank of the collision frequency:

as the no.of molecules increase the collision frequency increase and depend also on the velocity and it's here the same.

∴ Collision frequency will only depend on the no.of molecules

we have no.of molecules of A > B > C as Mw A < B < C 

∴the rank of the collision frequency is:

A > B > C 

6 0
3 years ago
What influence does social media have on social scientist
Nesterboy [21]
It helps them figure out more in dept about education.
5 0
3 years ago
The lone pair of electrons on the oxygen atom in an ester can form hydrogen bonds in some situations, but esters cannot form hyd
mixer [17]

Answer:

Esters have lower boiling point than alcohols.

Explanation:

Esters are the fruity smelling compounds which are formed from carboxylic acid and alcohol with the removal of water.

The general formula for the ester is RCOOR' which is prepared from RCOOH acid and R'OH alcohol.

Ester can not form strong hydrogen bond as there is no hydrogen attached to the electronegative atom in the ester and thus cannot form hydrogen bonds with each other.<u> Due to this factor, the interactions within the molecules of the ester is lower than that of alcohols which exist in strong hydrogen bonding. As a result, ester can be easily boiled when compared to the alcohols and thus they have lower value of boiling points.</u>

4 0
3 years ago
Which of the following elements is found in the p sublevel?<br> O Ti<br> O Li<br> ОСІ<br> O He
ICE Princess25 [194]

Answer:

OC I

Explanation:

can't explain srry

8 0
3 years ago
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