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PSYCHO15rus [73]
2 years ago
14

Please answer the question that is attached to this question. It will be a BIG help for my homework if you give a proper explana

tion. I promise I will eventually give brainly for the best answer.

Chemistry
1 answer:
vichka [17]2 years ago
8 0
Naw man I ain’t the correct answer
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Identify each element below, and give the symbols of the other elements in its group:
Misha Larkins [42]

Answer:

Answer in explanation

Explanation:

a. Boron , element 5

Helium has 2 electrons, add to the other 3 to give 5.

Other group members are : Aluminum Al, Gallium Ga, Indium In , Thallium Tl and Nihonium Nh

b. Sulphur, element 16

Neon is 10 , add other 6 electrons to make 16

Other group members are: Oxygen O, selenium Se , Tellurium Te and Polonium Po

c. Lanthanum, element 57

Xenon is 54, add the other 3 electrons to give 57.

Other elements in group : Scandium Sc , Yttrium Y , Actinium Ac, Lutetium Lu and/or Lawrencium Lr

4 0
3 years ago
Which is true of binary ionic compounds?
Dmitry [639]

Answer:

Its a or d if im stupid my b

Explanation:

4 0
3 years ago
Calculate the standard enthalpy change for the reaction at 25 ∘C. Standard enthalpy of formation values can be found in this lis
weqwewe [10]

Answer:

\Delta H_{rxn}=-2043.999kJ

Explanation:

\Delta H_{rxn}^{0}=\sum [n_{i}\times \Delta H_{f}^{0}(product)_{i}]-\sum [n_{j}\times \Delta H_{f}^{0}(reactant_{j})]

Where n_{i} and n_{j} are number of moles of product and reactant respectively (equal to their stoichiometric coefficient).

\Delta H_{f}^{0} is standard heat of formation and \Delta H_{rxn}^{0} is standard enthalpy change for reaction at 25^{0}\textrm{C}

So, \Delta H_{rxn}=[3mol\times \Delta H_{f}^{0}(CO_{2})_{g}]+[4mol\times \Delta H_{f}^{0}(H_{2}O)_{g}]-[1mol\times \Delta H_{f}^{0}(C_{3}H_{8})_{g}]-[5mol\times \Delta H_{f}^{0}(O_{2})_{g}]

or, \Delta H_{rxn}=[3mol\times -393.509kJ/mol]+[4mol\times -241.818kJ/mol]-[1mol\times -103.8kJ/mol]-[5mol\times 0kJ/mol]

or, \Delta H_{rxn}=-2043.999kJ

4 0
3 years ago
Which of the following explains why the lab safety policy specifically addresses loose clothing, contact lenses, and large, loos
valentina_108 [34]

Answer:

b. Loose clothing and jewelry is more likely to impede movement, or accidentally knock materials over, causing a spill or other accident.

Explanation:

Hello,

During the laboratories, a high dexterity is required, thus, such accessories,  when you move or change your duty, could touch other materials or act out of your control resulting in spillages and constricting your proper movements and skills, that is why considering the lab safety policy, we must take those artifacts away from the chemistry lab.

Best regards.

3 0
3 years ago
Match each group on the periodic table with its description. HELP ME PLS
Artist 52 [7]
Very reactive nonmetals.
3 0
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