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postnew [5]
2 years ago
11

What is the quotient and the remainder of 7 divided by 5839

Mathematics
1 answer:
eduard2 years ago
4 0

Answer: 834.142857143

Step-by-step explanation: I did it on paper this is like 3rd grade math.

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Write A expression for increased by 23
Akimi4 [234]

Answer:

5+23

Step-by-step explanation:

increased by is another word for add

7 0
3 years ago
Read 2 more answers
F(x)=-x^2+8x+15 ...?
rusak2 [61]
Here i how I would do it:<span>f(x)=−<span>x2</span>+8x+15</span>
set f(x) = 0 to find the points at which the graph crosses the x-axis. So<span>−<span>x2</span>+8x+15=0</span>
multiply through by -1<span><span>x2</span>−8x−15=0</span> <span>(x−4<span>)2</span>−31=0</span> <span>x=4±<span>31<span>−−</span>√</span></span>
So these are the points at which the graph crosses the x-axis. To find the point where it crosses the y-axis, set x=0 in your original equation to get 15. Now because of the negative on the x^2, your graph will be an upside down parabola, going through<span>(0,15),(4−<span>31<span>−−</span>√</span>,0)and(4+<span>31<span>−−</span>√</span>,0)</span>
To find the coordinates of the maximum (it is maximum) of the graph, you take a look at the completed square method above. Since we multiplied through by -1, we need to multiply through by it again to get:<span>f(x)=31−(x−4<span>)2</span></span><span>
Now this is maximal when x=4, because x=4 causes -(x-4)^2 to vanish. So the coordinates of the maximum are (4,y). To find the y, simply substitute x=4 into the equation f(x) to give y = 31. So it agrees with the mighty Satellite: (4,31) is the vertex.</span>
8 0
3 years ago
Multiply the polynomials.<br> (4x- + 4x + 6)(7x + 5)
SashulF [63]

\implies {\blue {\boxed {\boxed {\purple {\sf {   \: 28 {x}^{3}  + 48 {x}^{2}  + 62x + 30}}}}}}

\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}

(4 {x}^{2}  +  4x + 6)(7x + 5)

= \: 7x(4 {x}^{2}  + 4x + 6) + 5(4 {x}^{2}  + 4x + 6)

=  \: 28 {x}^{3}  + 28 {x}^{2}  + 42x + 20 {x}^{2}  + 20x + 30

Combining like terms, we have

=  \: 28 {x}^{3}  + (28 {x}^{2}  + 20 {x}^{2} ) + (42x + 20x) + 30

=  \: 28 {x}^{3}  + 48 {x}^{2}  + 62x + 30

\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}

3 0
3 years ago
The longer leg of a right triangle is 4 more than the short leg. The hypotenuse is eight less than the sum of the 2 legs.
Crazy boy [7]

Answer:

SteLet a = short leg of the right triangle, b = the longer leg, and c = the hypotenuse.

The longer leg of a right triangle is 4inches longer than the shorter leg: b = a + 4

The hypotenuse is 8inches longer than the shorter leg:  c = a + 8

 

Use the Pythagorean Theorem:

 

a2 + b2 = c2

a2 + (a+4)2 = (a+8)2

a2 + a2 + 8a + 16 = a2 + 16a + 64

a2 - 8a - 48 = 0

 

Factors to:

 

(a-12)(a+4) = 0

a = 12, -4

 

Since we can't have a side of -4, a = 12

Shorter Leg = 12 inches

Longer Leg = 12 + 4 = 16 inches

Hypotenuse = 12 + 8 = 20 inches

6 0
3 years ago
Help question 4 pleaseeeeeeee
KIM [24]
The anwser is D and I’m sure of it
6 0
3 years ago
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