Answer:
2.60 moles of A remaining.
Explanation:
According to Le Chatelier's principle, the equilibrium would shift if the volume, concentration, pressure, or temperature changes.
In this question, we were told that the volume doubles, that implies that we would have to double the molarity of B/ C (since B=C.)
However, it is obvious and clear from the given equation of the reaction that A is solid in it's activity = 1. Hence, it is then ignored.
So doubling B would be 1.30 M × 2 = 2.60 M
i.e 2.60 M moles of A was consumed.
Now; the number of moles of A remaining is 5.20 - 2.60 = 2.60 moles of A remaining.
Answer:
Distance cover = 8 km
Explanation:
Given:
Speed of runner = 4 km/h
Time taken = 2 hour
Find:
Distance cover
Computation:
Distance = Speed x Time
Distance cover = Speed of runner x Time taken
Distance cover = 4 x 2
Distance cover = 8 km
I believe that the answer would be A. Tree
(Plus I took the assessment like this sooo, Im 100% this is correct)
Answer:
a. C₄H₁₀/O₂ = 2:13 (example)
b. O₂/CO₂ = 13:8
c. O₂/H₂O = 13:10
d. C₄H₁₀/CO₂ = 2:8
e. C₄H₁₀/H₂O = 2:10
Explanation:
2C₄H₁₀ + 13O₂ ⟶ 8CO₂ + 10H₂O
The molar ratios are the same as the coefficients in front of the formulas.
The given question is incomplete. The complete question is as follows.
A 2.300×10−2 m solution of nacl in water is at 20.0∘c. the sample was created by dissolving a sample of nacl in water and then bringing the volume up to 1.000 l. it was determined that the volume of water needed to do this was 999.4 ml . the density of water at 20.0∘c is 0.9982 g/ml.
Calculate the molality of the salt solution.
Express your answer to four significant figures and include the appropriate units.
Explanation:
Molality is defined as the number of moles present in kg of a solvent.
Mathematically, Molality = 
Also,
Mole of solute = Molarity of solute x Volume of solution
= (0.0230 M) x (1.000 L) = 0.0230 mol of solute
Therefore, mass of solvent will be as follows.
= 997.7 g
= 0.9977 kg (as 1 kg = 1000 g)
Therefore, we will calculate the molality as follows.
Molality = 
= 0.02306 mol/kg
thus, we can conclude that molality of the given solution is 0.02306 mol/kg.
