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choli [55]
3 years ago
12

What is the most important requirement for all living things? water carbon dioxide light vitamins

Chemistry
2 answers:
Sidana [21]3 years ago
5 0
Water. All organisms that depend on oxygen need water to live.
valentinak56 [21]3 years ago
4 0

Water is the essential thing, since we are talking about ALL living organisms. The most basic and important necessity they all share is the need to hydrate.

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ANSWER THIS PLS IM LEGIT DYING HERE
Free_Kalibri [48]
<span>In the written directions the indicator that the matter contains protein is when the solution turns a purple color. Therefore we can conclude that if your sample causes the solution of Copper Sulfate and Sodium Hydroxide to turn purple, it does indeed contain protein.</span>
8 0
3 years ago
Read 2 more answers
Calculate the average atomic mass of Mg if the naturally occurring isotopes are Mg - 24, Mg - 25 and Mg - 26. Their masses and a
Elenna [48]

Answer:

24.309

Explanation:

mass×percentage+.. = average amu

23.985×78.7/100+24.986×10.13/100+25.983×11.17/100

to three decimal places

=24.309

5 0
1 year ago
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ch4aika [34]

Answer:

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3 0
3 years ago
Disagree or agree n provide evidence !!! pls n thank you​
stealth61 [152]

Answer: True

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5 0
2 years ago
When 1.025 g of naphthalene (c10h8) burns in a bomb calorimeter, the temperature rises from 24.25°c to 32.33°c. find δerxn for t
Goryan [66]

Answer : The \Delta E for the combustion of naphthalene is 5161.25KJ/mole

Solution : Given,

Mass of naphthalene = 1.025 g

Initial temperature = 24.25^oC

Final temperature = 32.33^oC

Specific heat capacity of calorimeter = 5.11KJ/^oC

Molar mass of naphthalene = 128 g/mole

First, we have to calculate the heat absorbed, q

Formula used :

q=c\times \Delta T=c\times (T_{final}-T_{initial})

Now put all the given values in this formula, we get

q=(5.11KJ/^oC)\times (32.33^oCT-24.25^oC)=41.29KJ

Now we have to calculate the moles of naphthalene.

Moles of C_{10}H_{8} = \frac{\text{ Mass of }C_{10}H_{8}}{\text{ Molar mass of }C_{10}H_{8}}=\frac{1.025g}{128g/mole}=0.0080moles

Now we have to calculate the \Delta E for combustion of naphthalene.

\Delta E=\frac{q}{n}

where,

q = heat absorbed

n = number of moles

Now put all the values in this formula, we get

\Delta E=\frac{41.29KJ}{0.0080moles}=5161.25KJ/mole

Therefore, the \Delta E for the combustion of naphthalene is 5161.25KJ/mole

6 0
2 years ago
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