Answer:
Explanation:
The equation that relates standard Gibbs free energy, ΔG, with equilibrium constant, K, is:
ΔG = -RT ln K
<em>Where R is gas constant, 8.314J/molK, and T is absolute temperatue (30.0°C + 273.15 = 303.15K).</em>
<em />
Replacing (110kJ = 110000J):
110000J/mol = -8.314J/molK*303.15K ln K
-43.644 = lnK
1.11x10⁻¹⁹ = K
<em />
The energy that an object has is moving
Answer:
pump that is the answer hope its right
Answer:
32000atm
Explanation:
Using Boyle's law equation;
P1V1 = P2V2
Where;
P1 = initial pressure (atm)
P2 = final pressure (atm)
V1 = initial volume (
V2 = final volume (L)
According to the question below:
P1 = 160.0 atm
P2 = 3.0 atm
V1 = 600L
V2 = ?
Using P1V1 = P2V2
160 × 600 = 3 × V2
96000 = 3V2
V2 = 96000/3
V2 = 32000atm
