Answer:
the catalyst is for activation energy
Answer:
There are 5.43 grams of NaOCl
Explanation:
The given percent by mass of the solute tells us that out of the 150 g of the solution, 3.62% are due solely to the solute.
In other words, <u>the mass of the solute in the solution is</u>:
- 150 g * 3.62/100 = 5.43 g
Thus, in 150 grams of the given bleach solution, there are 5.43 grams of sodium hypochlorite.
Answer:
15.4%
Explanation:
If Ka = 0.54 mM = 1.51x10⁻⁵
Then;
C₄H₈O₂ --------> C₄H₇O₂⁻ + H⁺
I 0.54x10⁻³ 0 0
E 0.54x10⁻³(1-x) 0.54x10⁻³x 0.54x10⁻³x
Recall that x is the percentage degree of dissociation
From the ICE table;
Ka = [C₄H₇O₂⁻] [ H⁺]/[C₄H₈O₂]
1.51x10⁻⁵=(0.54x10⁻³x) (0.54x10⁻³x)/ 0.54x10⁻³(1-x)
1.51x10⁻⁵ = 0.54x10⁻³x^2/1-x
1.51x10⁻⁵(1-x) = 0.54x10⁻³x^2
1.51x10⁻⁵ - 1.51x10⁻⁵x = 0.54x10⁻³x^2
Hence;
0.54x10⁻³x^2 + 1.51x10⁻⁵x - 1.51x10⁻⁵=0
x^2 + 0.028x - 0.028 = 0
Solving the quadratic equation here;
x = 0.154 or −0.182
Ignoring the negative result, x = 0.154
Hence, fraction of butanoic acid that is in the dissociated form in this solution = 15.4%
The compound 
will have a triple bond.
Explanation:
A compound which consists of carbon and hydrogen atoms is known as a hydrocarbon.
Alkanes, alkenes and alkynes are all hydrocarbons.
- General chemical formula of an alkane is
. In an alkane molecule, all the atoms will be bonded through single bonds.
For example, 
is propane.
- General chemical formula of an alkene is
. An alkene molecule will have atleast one double bond between two carbon atoms.
For example, 
is ethene.
- General chemical formula of an alkyne is
. An alkyne will have atleast one triple bond between two carbon atoms.
For example, is propyne.
Thus, we can conclude that out of the given options will have a triple bond.
