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Papessa [141]
3 years ago
6

Which of the following is not equal to 0.536 kilometers?

Chemistry
2 answers:
qwelly [4]3 years ago
5 0

Answer : The incorrect option is, 53.6 hectometers (hm)

Explanation :

(1) The conversion used from kilometers to hectometers is:

1 km = 10 hm

Converting the given value, we get:

\Rightarrow 0.536km\times (\frac{10hm}{1km})=5.36hm

The value in hectometers is 5.36 hm

(2) The conversion used from kilometers to meters is:

1 km = 1000 m

Converting the given value, we get:

\Rightarrow 0.536km\times (\frac{1000m}{1km})=536m

The value in meters is 536 m

(3) The conversion used from kilometers to millimeters is:

1 km = 1000000 mm

Converting the given value, we get:

\Rightarrow 0.536km\times (\frac{1000000mm}{1km})=536000mm

The value in millimeters is 536000 mm

(4) The conversion used from kilometers to centimeters is:

1 km = 100000 cm

Converting the given value, we get:

\Rightarrow 0.536km\times (\frac{100000cm}{1km})=53600cm

The value in centimeters is 53600 cm

Hence, the incorrect answer is, 53.6 hectometers (hm)

ladessa [460]3 years ago
3 0
53.6 hectometers is not equal to 0.536 kilometer
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3.0 L of oxygen gas is heated from 100k to 250k. What is the new volume after the temperature has been increased???
alexandr402 [8]

Answer:

7.5 L

Explanation:

Using Charles' law, which is V1/T1=V2/T2, we can plug in these numbers to find the answer.  The law states that volume is directly proportional to temperature. 3.0L/100K = x L / 250 K. Solve for x to get 7.5 L. Hope this helps.

7 0
3 years ago
Two isotopes of lithium are found in nature Li6 has a mass of 6. 02u and Li7 has a mass of 7.02u . Use the atomic weight of lith
alexandr402 [8]

The isotope that is more abundant, given the data is isotope Li7

<h3>Assumption</h3>
  • Let Li6 be isotope A
  • Let Li7 be isotope B

<h3>How to determine whiche isotope is more abundant</h3>
  • Molar mass of isotope A (Li6) = 6.02 u
  • Molar mass of isotope B (Li7) = 7.02 u
  • Atomic mass of lithium = 6.94 u
  • Abundance of A = A%
  • Abundance of B = (100 - A)%

Atomic mass = [(mass of A × A%) / 100] + [(mass of B × B%) / 100]

6.94 = [(6.02 × A%) / 100] + [(7.02 × (100 - A)) / 100]

6.94 = [6.02A% / 100] + [702 - 7.02A% / 100]

6.94 = [6.02A% + 702 - 7.02A%] / 100

Cross multiply

6.02A% + 702 - 7.02A% = 6.94 × 100

6.02A% + 702 - 7.02A% = 694

Collect like terms

6.02A% - 7.02A% = 694 - 702

-A% = -8

A% = 8%

Thus,

Abundance of B = (100 - A)%

Abundance of B = (100 - 8)%

Abundance of B = 92%

SUMMARY

  • Abundance of A (Li6) = 8%
  • Abundance of B (Li7) = 92%

From the above, isotope Li7 is more abundant.

Learn more about isotope:

brainly.com/question/24311846

#SPJ1

4 0
2 years ago
How many moles of carbon are there in 5 g of carbon?
Umnica [9.8K]

Answer:

0.416666667

Explanation:

number of moles= mass of sample ÷ molar mass

=5÷12

=0.41666667

8 0
3 years ago
An 8.0 L sample of neon gas at 300. K exerts a pressure of 900. kPa. If the gas is compressed to 2.0 L and the temperature is ra
svetoff [14.1K]

Answer:

7200 kPa

Explanation:

Applying,

PV/T = P'V'/T'................ Equation 1

Where P = Initial pressure of neon gas, V = Initial volume of neon gas, T = Initial temperature of neon gas, P' = Final pressure of neon gas, V' = Final volume of neon gas, T' = Final Temperature of neon gas

Make P' the subject of the equation

P' = PVT'/V'T.............. Equation 2

Given: P = 900 kPa, V = 8.0 L, T = 300 K, V' = 2.0 L, T' = 600 K

Substitute these values into equation 2

P' = (900×8×600)/(2×300)

P' = 7200 kPa

6 0
3 years ago
Which element has a higher first ionization energy than chlorine (Cl)?
4vir4ik [10]

Answer:

Argon

Explanation:

It has more electron than chlorine

6 0
3 years ago
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