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nikdorinn [45]
3 years ago
15

There is an analogy between rotational and linear physical quantities. what rotational quantities are analogous to distance and

velocity?
Physics
2 answers:
Scrat [10]3 years ago
8 0

Answer:

Rotational units can be said to be analogous to linear physical units, for example, linear distance is analogous to angular displacement, since angular displacement is defined as the distance a body travels in a rotary motion.

On the other hand, linear velocity is analogous to angular velocity, since said angular velocity is the angular distance that a body covers per unit of time.

Explanation:

SVEN [57.7K]3 years ago
5 0

ANSWER:

Angular displacement is analogous to distance.

Angular velocity is analogous to velocity.

EXPLANATION:

FOR  ANGULAR DISPLACEMENT AND DISTANCE

Angular displacement = theta

theta = s/r

s = linear dispalcement/distance

r= radius.

so ,

linear displacement/distance  s = theta * r.

FOR  ANGULAR VELOCITY AND VELOCITY

Angular velocity = w

w = v/r

v = velocity

r = radius

so,

velocity v = w * r.

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3 years ago
A disk of mass m and moment of inertia of I is spinning freely at 6.00 rad/s when a second identical disk, initially not spinnin
Nadusha1986 [10]

Answer:

The angular speed of the new system is 3\,\frac{rad}{s}.

Explanation:

Due to the absence of external forces between both disks, the Principle of Angular Momentum Conservation is observed. Since axes of rotation of each disk coincide with each other, the principle can be simplified into its scalar form. The magnitude of the Angular Momentum is equal to the product of the moment of inertial and angular speed. When both disks begin to rotate, moment of inertia is doubled and angular speed halved. That is:

I\cdot \omega_{o} = 2\cdot I \cdot \omega_{f}

Where:

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\omega_{o} - Initial angular speed, measured in radians per second.

\omega_{f} - Final angular speed, measured in radians per second.

This relationship is simplified and final angular speed can be determined in terms of initial angular speed:

\omega_{f} = \frac{1}{2}\cdot \omega_{o}

Given that \omega_{o} = 6\,\frac{rad}{s}, the angular speed of the new system is:

\omega_{f} = \frac{1}{2}\cdot \left(6\,\frac{rad}{s} \right)

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3 years ago
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Scilla [17]

Answer:

Option C is correct.

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Explanation:

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In this composite,

The fibres = 20 vol%

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Modulus of elasticity of the composite

= [0.2 × E(fibres)] + [0.8 × E(Al)]

Modulus of elasticity of the fibers = E(fibres) = (55 × 10⁶) psi. =

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[1 ÷ E(perpendicular)]

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[1 ÷ E(perpendicular)]

= [0.2 ÷ (55 × 10⁶)] + [0.8 ÷ (10 × 10⁶)]

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Hope this Helps!!!

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aksik [14]

Answer:

Explanation:

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