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Aleksandr [31]
3 years ago
15

A spring with k = 500 N/m stores 704 J. How far is it extended from the equilibrium position

Physics
1 answer:
kaheart [24]3 years ago
4 0

Given that:

k = 500 n/m,

work (W) = 704 J

spring extension (x) = ?

         we know that,

                      Work = (1/2) k x²

                          704 = (1/2) × 500 × x²

                            x = 1.67 m

A spring stretched for 1.67 m distance.

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Answer:

Explanation:

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a) For r>R,

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Equating both, we get

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2 years ago
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Answer:

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In that way, the expression x=V.t give us the displacement from t=0s until t=51s, but we have to sum the initial distance from the point A.

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Answer:

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