Let
F=tension of cable on the left
x=angle of left cable makes with the horizontal
Resolve forces vertically (y-direction)
331=550sin(12)+Fsin(x) =>
Fsin(x)=331-550sin(12)=216.649..........(1)
Resolve forces horizontally (x-direction)
Fcos(x)=550cos(12) =>
Fcos(x)=537.981............................(2)
Divide (1) by (2)
tan(x)=Fsin(x)/Fcos(x)=0.40271
x=atan(0.40271) = 21.935 °
From (2),
F=537.981/cos(x)=537.981/0.92761 = 579.965 N
Check:
Fsin(x)+550sin(12)=579.965*sin(21.935)+550*sin(12) = 331.000 ok
Fcos(x)=537.981
550sin(12)=537.981 ok
The distance of dodo is 150 cm.
<h3>What is focal length of lens?</h3>
The distance between a lens's center and its focal point is its focal length. A focal point is a location on the principal axis where, following refraction via the lens, light rays parallel to the principal axis either actually meet or appear to meet.
Given parameters:
the focal length of David's lens is: f = 50 cm.
magnification is: m = -0.50
We have to find: distance of dodo, that is, object's distance : u = ?
We know that:
u =f( 1/m -1)
⇒ u = 50(-1/0.50-1) = - 150 cm.
Hence, distance is 150 cm.
Learn more about focal length here:
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Answer:
Florida is tropical, with a significant rainy seson
Answer:
Explanation:
This problem relates to interference of light in thin films .
The condition of bright fringe in thin films which is sandwitched by two layers of medium having lesser refractive index is as follows.
2nt = (2n+1) λ / 2 , n is refractive index of thin layer , t is its thickness , λ is wavelength of light .
2 x 1.5 t = λ / 2 , if n = 0 for minimum thickness.
2 x 1.5 t = 600 / 2 nm
t = 100 nm .
This is the answer: Fossil's found in Susan's yard are from prehistoric times.
