The cardiovascular system consists of

How much current will pass through a 12.5 ohm resistor when it is connected to ta 115 volt source of electrical potential?

Marrrta [24]

Answer:

9.2 amperes

Explanation:

Ohm's law states that the voltage V across a conductor of resistance R is given by $V = R I$

Here, voltage V is proportional to the current I.

For voltage, unit is volts (V)

For current, unit is amperes (A)

For resistance, unit is Ohms (Ω)

Put R = 12.5 and V = 115 in V=RI

$115=12.5I\\I=\frac{115}{12.5}\\ =9.2\,\,amperes$

8 0

3 years ago

When Earth and the Moon are separated by a

Wewaii [24]

Using the Universal Gratitation Law, we have:

$F= \frac{MmG}{d^2} \\ MmG=2*10^{20}*(3.84*10^8)^2 \\ MmG=29.4912*10^36$

Again applying the formula in the new situation, comes:

$F= \frac{MmG}{d^2} \\ F= \frac{29.4912*10^36}{(1.92*10^8)^2} \\ \boxed {F=8*10^{20}}$

Number 4

If you notice any mistake in my english, please let me know, because i am not native.

6 0

3 years ago

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In the equation for the gravitational force between two objects, what does G represent? the gravitational constant the gravitati

kumpel [21]

G is the gravitational constant, which is approximately 6.6x10^-11 Nm/s^2. It has the same value regardless of the masses of both objects or the distance between them.

3 0

3 years ago

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Ignoring the electron spin what is the largest possible energy difference, if the magnetic field is 2.02 tesla?

Nonamiya [84]

Complete Question:

When specially prepared Hydrogen atoms with their electrons in the 6f state are placed into a strong uniform magnetic field, the degenerate energy levels split into several levels. This is the so called normal Zeeman effect.

Ignoring the electron spin what is the largest possible energy difference, if the magnetic field is 2.02 Tesla?

Answer:

ΔE = 1.224 * 10⁻²² J

Explanation:

In the 6f state, the orbital quantum number, L = 3

The magnetic quantum number, $m_{L} = -3, -2, -1, 0, 1, 2, 3$

The change in energy due to Zeeman effect is given by:

$\triangle E = m_{L} \mu_{B} B$

Magnetic field B = 2.02 T

Bohr magnetron, $\mu_{B} = 9.274 * 10^{-24} J/T$

$\triangle E = 6 * 9.274 * 10^{-24} * 2.2\\$

ΔE = 1.224 * 10⁻²² J

5 0

3 years ago

What is the tangential velocity of a record player which makes 11 revolutions in 20 seconds?

slava [35]

Answer:

The tangential velocity of a rotating object is:

v = r*w

where r is the radius, and w is the angular velocity.

w = 2*pi*f

where f is the frequency.

We know that the record plater does 11 revolutions in 20 seconds, then it does:

11 rev/20s = 0.55 rev/s = f

then we have:

w = 2*pi*0.55 s^-1 = 2*3.14*0.55 s^-1 = 3.454 s^-1

The radius of a record player is really variable, it is around 10 inches, so i will use r = 10in, which is the rotating part of the record player.

then the tangential velocity is:

v = 10in*3.454 s^-1 = 34.54 in/s

7 0

3 years ago