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olganol [36]
3 years ago
8

What is the volume of a cube with a higher base and width of 4cm

Mathematics
1 answer:
katrin2010 [14]3 years ago
6 0
<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ Volume = height x base x width

Volume = 4 x 4 x 4

Volume = 64

The volume is 64cm^2

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

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Find the Perimeter of the figure below, composed of a rectangle and two
larisa [96]

Answer:

Step-by-step explanation:

3 0
3 years ago
A = {1, 3, 5, 7, 9}
kondor19780726 [428]
The \cap symbol means intersection, so everything that is in both sets, and the \cup symbol means union, so the two sets combined.

B \cup C = \{1, 2, 4, 5, 6, 7, 8, 9, 10\} = S
A \cap S= \{1, 5, 7, 9\}

So the answer is A.

7 0
3 years ago
If the points (-8, 7) and T (6,-3) are on a line segment, find the length of ST.​
larisa86 [58]

Answer:

The answer is

<h2>2√74 or 17.20 units</h2>

Step-by-step explanation:

The length of w line segment between two points can be found by using the formula

d =  \sqrt{ ({x1 - x2})^{2} +  ({y1 - y2})^{2}  }  \\

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

S(-8, 7) and T (6,-3)

The length of ST is

|ST|  =  \sqrt{ ({ - 8 - 6})^{2} +  ({7 + 3})^{2}  }  \\  =  \sqrt{ ({ - 14})^{2} +  {10}^{2}  }  \\  =  \sqrt{196 + 10}  \\  =  \sqrt{296}  \\  = 2 \sqrt{74}  \\  = 17.2046505...

We have the final answer as

<h3>2√74 or 17.20 units</h3>

Hope this helps you

8 0
3 years ago
What is 8(2x-3)-6x if x = 3
KengaRu [80]
8(2x - 3)-6x

First, replace all the x's with 3s. Simplfy 2 × 3 to 6. / Your problem should look like: 8 × (6 - 3) - 6 × 3
Second, simplify 6 - 3 to 3. / Your problem should look like: 8 × 3 - 6 × 3
Third, simplify 8 × 3 to 24. / Your problem should look like: 24 - 6 × 3
Fourth, simplify 6 × 3 to 18. / Your problem should look like: 24 - 18
Fifth, simplify 24 - 18 to get 6. / Your problem should look like: 6

Answer: 6

4 0
3 years ago
I need help please it’s really hard and I don’t understand it
mr_godi [17]

The line segment HI has length 3<em>x</em> - 5, and IJ has length <em>x</em> - 1.

We're told that HJ has length 7<em>x</em> - 27.

The segment HJ is made up by connecting the segments HI and IJ, so the length of HJ is equal to the sum of the lengths of HI and IJ.

This means we have

7<em>x</em> - 27 = (3<em>x</em> - 5) + (<em>x</em> - 1)

Solve for <em>x</em> :

7<em>x</em> - 27 = (3<em>x</em> + <em>x</em>) + (-5 - 1)

7<em>x</em> - 27 = 4<em>x</em> - 6

7<em>x</em> - 4<em>x</em> = 27 - 6

3<em>x</em> = 21

<em>x</em> = 21/3

<em>x</em> = 7

5 0
3 years ago
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