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3 years ago

Alex can ski 960 meters in 5 minutes. If his skiing speed is increased by 20 m/min, how many meters can he cover in 10 minutes?

Physics

2 answers:

Scrat [10]3 years ago

8 0

Answer:

200

Explanation:

zhuklara [117]3 years ago

6 0

Your answer will be that Alex will go 2520 meters in 10 minutes.

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A ball of mass 0.200kg with a velocity of 1.50i^m/s meets a ball of mass 0.300kg with a velocity of -0.400 i^ m/s in a head-on,

Monica [59]

Velocities of their center of mass after collisions are found by the following formula as shown in the image:

<h3>What are elastic collisions?</h3>

An elastic collision is one in which there is no energy lost during the impact. A moderately inelastic collision occurs when some energy is wasted yet the items do not cling together. The maximum amount of energy is wasted when the objects collide in a perfectly inelastic impact. The kinetic energy doesn't change.
It may be two dimensions or one dimension. Because there will always be some energy exchange, no matter how tiny, totally elastic collision is not conceivable in the real world.
While the overall system's linear momentum does not change, the individual momenta of the participating components do, and because these changes are equal and opposite in size and cancel each other out, the initial energy is conserved.

To learn more about Elastic collisions refer to:

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2 years ago

The red LED consists of a white LED covered with a red filter. What does the red filter do?

telo118 [61]

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3 years ago

Drug abuse is characterized by _____.

arlik [135]

There can be mental health effects and psychological dependence

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3 years ago

Read 2 more answers

A force that tends to pull an object towards the center of the earth is?

In-s [12.5K]

Explanation:

Gravitational force

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4 years ago

A 60 g ball is dropped from rest from a height of 2.4 m. It bounces off the floor and rebounds to a maximum height of 1.9 m. If

kap26 [50]

Answer:

The force is 1.34 newtons and its direction is upward.

Explanation:

Choosing positive direction pointing towards the floor in this collision we're going to use the momentum-impulse theorem that states:

$J=\Delta p$ (1)

with $\Delta p=p_f-p_i$ the change in the momentum and J the impulse, with pi the initial momentum that is the momentum just before the collision and pf the final momentum th is the momentum just after the collision. The impulse J is also defined as:

$J=F_{avg}\Delta t$ (2)

with $F_{avg}$ the average force and $\Delta t$ the time the collision lasts

We can equate expressions (2) and (1):

$\Delta p=p_f-p_i=F_{avg}\Delta t$

Using the definition of linear momentum as mass (m) time velocity (v):

$mv_f-mv_i=F_{avg}\Delta t$

We can solve for Favg:

$F_{avg}=\frac{m(v_f-v_i)}{\Delta t}$ (3)

Now we should find the velocities vf and vi, we should do this using conservation of energy:

For the velocity the ball has just before reaches the floor:

$U_i=K_f$

With Ui the initial potential energy (there is not initial kinetic energy) and Kf the final kinetic energy (there is not final potential energy), then:

$mgh=\frac{mv_i^2}{2}$

solving for vi:

$v_i=\sqrt{2gh}=\sqrt{2*9.81*2.4}=6.86\frac{m}{s}$

For the velocity the ball has just after bounces the floor:

$K_i=U_f$

There is not initial potential energy because it's a floor level at this instant, and the there is not final kinetic energy because the ball has instantly zero velocity at its maximum height (hm), then:

$\frac{mf_i^2}{2}=mgh_m$

solvig for vf:

$v_f=\sqrt{2gh_m}=\sqrt{2*9.81*1.9}=6.10\frac{m}{s}$

Using vf and vi on (3):

$F_{avg}=\frac{(0.06)(6.10-6.86)}{0.034}=-1.34 N$

The negative sign indicates the direction of the force is pointing away the floor

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3 years ago