The answer is: Ammonium hydroxide would be found in the pantry because it is found in vinegar.
Ammonim hydroxide (NH₄OH) is base and vinegar is acid.
pH of ammonium hydroxide is greater than 7 and vinegar has pH less than 7.
Ammonium hydroxide is a smelling, colorless liquid.
It is used as cleaning product, disinfectants and stain treaters.
Household ammonia contains 5-10% ammonium hydroxide.
Answer:
C. have specific jobs
Explanation:
If an organism has specialized cells, then the cells performs specific jobs.
A group of cells that performs a specific job is called tissues.
- In higher organisms, cells are specialized for specific purposes in them.
- This is to ensure that cells are optimized to carry out certain functions.
- Specialization of cells usually occurs by cellular differentiation when an organism begins to form.
<span>A supposition or proposed explanation made on the basis of limited evidence as a starting point for further investigation.</span>
Answer:
-21 kJ·mol⁻¹
Explanation:
Data:
H₃O⁺ + OH⁻ ⟶ 2H₂O
V/mL: 50 50
c/mol·dm⁻³: 1.0 1.0
ΔT = 4.5 °C
C = 4.184 J·°C⁻¹g⁻¹
C_cal = 50 J·°C⁻¹
Calculations:
(a) Moles of acid

So, we have 0.050 mol of reaction
(b) Volume of solution
V = 50 dm³ + 50 dm³ = 100 dm³
(c) Mass of solution

(d) Calorimetry
There are three energy flows in this reaction.
q₁ = heat from reaction
q₂ = heat to warm the water
q₃ = heat to warm the calorimeter
q₁ + q₂ + q₃ = 0
nΔH + mCΔT + C_calΔT = 0
0.050ΔH + 100×4.184×4.5 + 50×4.5 = 0
0.050ΔH + 1883 + 225 = 0
0.050ΔH + 2108 = 0
0.050ΔH = -2108
ΔH = -2108/0.0500
= -42 000 J/mol
= -42 kJ/mol
This is the heat of reaction for the formation of 2 mol of water
The heat of reaction for the formation of mol of water is -21 kJ·mol⁻¹.
Answer:
The flow rate would be 22.5ml/hr
Explanation:
Volumetric flow rate = Mass flow rate ÷ density
Mass flow rate = 3mg/min = 3mg/min × 60min/1hr = 180mg/hr
Density = mass/volume = 2g/250ml = 0.008g/ml = 0.008g/ml × 1000mg/1g = 8mg/ml
Volumetric flow rate = 180mg/hr ÷ 8mg/ml = 22.5ml/hr