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IgorLugansk [536]
3 years ago
11

Like stoichiometry involving mass quantities, stoichiometry involving solutions always includes _____________.

Chemistry
1 answer:
Luda [366]3 years ago
4 0
<span>Answer:
             Like Stoichiometry involving mass quantities, Stoichiometry involving solutions always includes <u>Volumes</u>.

Explanation:
                   Stoichiometry involves calculations related to amount of reactants and products in a reaction. Further, Stoichiometry is divided as,

                   a) Solution Stoichiometry:
                                                           It is based on calculations related to the volume of reactants and products in a solution.

                    b) Gravimetric Stoichiometry:
                                                           It is basically based on the masses of reactants and products in a reaction.

                    c) Gas Stoichiometry:
                                                      It involves the volume of gases in reactant and product side.</span>
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Microwave radiation has a wavelength on the order of 1.0 cm. Calculate the frequency and the energy of a single photon of this r
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Answer :

(1) The frequency of photon is, 3\times 10^{10}Hz

(2) The energy of a single photon of this radiation is 1.988\times 10^{-23}J/photon

(3) The energy of an Avogadro's number of photons of this radiation is, 11.97 J/mol

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Wavelength of photon = 1.0cm=0.01m     (1 m = 100 cm)

(1) Now we have to calculate the frequency of photon.

Formula used :

\nu=\frac{c}{\lambda}

where,

\nu = frequency of photon

\lambda = wavelength of photon

c = speed of light = 3\times 10^8m/s

Now put all the given values in the above formula, we get:

\nu=\frac{3\times 10^8m/s}{0.01m}

\nu=3\times 10^{10}s^{-1}=3\times 10^{10}Hz    (1Hz=1s^{-1})

The frequency of photon is, 3\times 10^{10}Hz

(2) Now we have to calculate the energy of photon.

Formula used :

E=h\times \nu

where,

\nu = frequency of photon

h = Planck's constant = 6.626\times 10^{-34}Js

Now put all the given values in the above formula, we get:

E=(6.626\times 10^{-34}Js)\times (3\times 10^{10}s^{-1})

E=1.988\times 10^{-23}J/photon

The energy of a single photon of this radiation is 1.988\times 10^{-23}J/photon

(3) Now we have to calculate the energy in J/mol.

E=1.988\times 10^{-23}J/photon

E=(1.988\times 10^{-23}J/photon)\times (6.022\times 10^{23}photon/mol)

E=11.97J/mol

The energy of an Avogadro's number of photons of this radiation is, 11.97 J/mol

3 0
3 years ago
Read 2 more answers
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