How many milliliters of sodium metal, with a density of 0.97 g/mL, would be needed to produce 12.8 grams of hydrogen gas in the
1 answer:
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Answer:
[IBr] = 0.049 M.
Explanation:
Hello there!
In this case, according to the balanced chemical reaction:
It is possible to set up the following equilibrium expression:
Whereas the the initial concentrations of both iodine and bromine are 0.50 M; and in terms of (reaction extent) would be:
Which can be solved for to obtain two possible results:
Whereas the correct result is 0.0245 M since negative results does not make any sense. Thus, the concentration of the product turns out:
Regards!
Answer:
<h2>0.102 L</h2>Explanation:
The new pressure can be found by using the formula for Boyle's law which is
Since we are finding the new volume
From the question we have
We have the final answer as
<h3>0.102 L</h3>Hope this helps you