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Daniel [21]
3 years ago
8

How many milliliters of sodium metal, with a density of 0.97 g/mL, would be needed to produce 12.8 grams of hydrogen gas in the

single replacement reaction below? Show all steps of your calculation as well as the final answer.
unbalanced equation: Na + H2O -> NaOH + H2
Chemistry
1 answer:
Hatshy [7]3 years ago
4 0
The balanced chemical reaction is:

<span>2Na + 2H2O -> 2NaOH + H2
</span>
We are given the amount of hydrogen gas produced by the reaction. This amount will be the starting point for our calculations.

12.8 g H2 ( 1 mol H2/ 2.02 g H2) ( 2 mol Na / 1 mol H2) (22.99 g Na / 1 mol Na ) (1 mL / 0.97 g) = 606.75 mL Na is needed
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Answer:

According to Le-chatelier principle, equilibrium will shift towards left to minimize concentration of OH^{-} and keep same equilibrium constant

Explanation:

In this buffer following equilibrium exists -

NH_{3}(aq.)+H_{2}O(l)\rightleftharpoons NH_{4}^{+}(aq.)+OH^{-}(aq.)

So, OH^{-} is involved in the above equilibrium.

When a strong base is added to this buffer, then concentration of OH^{-} increases. Hence, according to Le-chatelier principle, above equilibrium will shift towards left to minimize concentration of OH^{-} and keep same equilibrium constant.

Therefore excess amount of OH^{-} combines with NH_{4}^{+} to produce ammonia and water. So, effect of addition of strong base on pH of buffer gets minimized.

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Answer:

See Explanation

Explanation:

In electrophilic aromatic substitution, the benzene ring undergoes substitution when it is reacted with suitable electrophiles.

The products of electrophilic aromatic substitution depends on the substituents already present on the benzene ring. Some substituents activate the ring towards electrophilic substitution and direct the incoming electrophile to the ortho and para positions on the ring while some substituents deactivate the benzene ring towards electrophilic substitution and direct the incoming electrophlle to the meta position on the ring.

The amide substituent is moderately activating and is an ortho, para director hence the products shown in the mage attached to this answer.

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Answer:

The overview of the subject is outlined underneath in the summary tab.

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  • This ratio just says the reactant proportion which reacts, but not the exact quantity of the reacting product. Consequently, the molar ratio should only be used to provide theoretical instead of just a definite mass ratio.

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