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Daniel [21]
3 years ago
8

How many milliliters of sodium metal, with a density of 0.97 g/mL, would be needed to produce 12.8 grams of hydrogen gas in the

single replacement reaction below? Show all steps of your calculation as well as the final answer.
unbalanced equation: Na + H2O -> NaOH + H2
Chemistry
1 answer:
Hatshy [7]3 years ago
4 0
The balanced chemical reaction is:

<span>2Na + 2H2O -> 2NaOH + H2
</span>
We are given the amount of hydrogen gas produced by the reaction. This amount will be the starting point for our calculations.

12.8 g H2 ( 1 mol H2/ 2.02 g H2) ( 2 mol Na / 1 mol H2) (22.99 g Na / 1 mol Na ) (1 mL / 0.97 g) = 606.75 mL Na is needed
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How many molecules of n2 are in a 200.0 ml container at 780 mmhg and 135∘c?
Neporo4naja [7]
By  use  of  ideal  gas  equation   PV=  nRT     where  n  is  the  number  of  moles,P =  pressure, V   =  volume,  R=  gas  constant  (0.08206 L. atm/ mol.k)     ant  T  is  the  temperature,  

to  calculate  the  number  of  moles(n) =PV/RT

convert  ml  to L,  that  is  200/1000= 0.2  L

convert  mmHg  to  atm,  that  is  780mm hg  x  1atm/  760  mm  hg=  1.026  atm

convert  temperature  to   kelvin,  that  is 135  +273=  408  k
n  is  therefore=  (0.2  x   1.026)/ ( 0.08206  x   408)=  6.129  x10^-3   moles

from  avogadro  constant    1moles  =  6.02  x10^23  molecules   what  about  6 .129  x10^-3  moles

= ( 6.02  x10^23)  x (6.129 x10^-3)/  1mole =  3.69  x10^21  molecules
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