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Gekata [30.6K]
3 years ago
11

Which substances dissolves in pure water and produces a solution that is a good conductor of electricity?

Chemistry
2 answers:
lyudmila [28]3 years ago
4 0
CaCl2 is a good conductor of electricity when dissolved in water.
Elanso [62]3 years ago
4 0

Answer:

CaCl_2

Explanation:

We have to keep in mind that a <u>good conductor</u> would be a substance that has the ability to produce <u>ions</u> (<u>charged species</u>). These species are responsible for the electricity conduction on water.

Therefore, we have to check which ones of these compounds will produce <u>ions in water</u>. For N_2 and O_2 we have <u>diatomic</u> molecules (also gases) this type of molecules don't have the ability to produce ions due to his simplicity, they already are <u>very stable</u>.

In the sugar molecule C_6H_12O_6 we have a <u>covalent compound</u>. The ions are produced by <u>ionic compounds</u>. So, this molecule can be discarded too.

For CaCl_2 we have an ionic compound that have the ability to produce ions:

CaCl_2~~->~~Ca^+^2~+~2Cl^-

So, this is the compound that would be a good conductor due to the Ca^+^2 and the Cl^- ions.

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The rate constant for the decomposition of nitrogen dioxide NO2(g) LaTeX: \longrightarrow⟶ NO (g) + 1/2 O2(g) with a laser beam
aleksley [76]

Answer :

The time taken by the reaction is 19.2 seconds.

The order of reaction is, second order reaction.

Explanation :

The general formula to determine the unit of rate constant is:

(Concentration)^{(1-n)}(Time)^{-1}

Unit of rate constant                           Order of reaction

Concentration/Time                                        0

Time^{-1}                                                              1

(Concentration)^{-1}Time^{-1}                                 2

As the unit of rate constant is M^{-1}min^{-1}. So, the order of reaction is second order.

The expression used for second order kinetics is:

kt=\frac{1}{[A_t]}-\frac{1}{[A_o]}

where,

k = rate constant = 1.95M^{-1}s^{-1}

t = time = ?

[A_t] = final concentration = 0.97 M

[A_o] = initial concentration = 2.48 M

Now put all the given values in the above expression, we get:

1.95\times t=\frac{1}{0.97}-\frac{1}{2.48}

t=0.32min=0.32\times 60s=19.2s

Therefore, the time taken by the reaction is 19.2 seconds.

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4. linear momentum
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7 0
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