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sweet-ann [11.9K]
3 years ago
11

How many neutrons are present in an atom of

Chemistry
1 answer:
Tamiku [17]3 years ago
4 0
There’s going to be 8 neutrons presented
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Claude Bernard first recognized _____.
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Answer : Option B) Plant stomata opening and closing to maintain homeostasis.

Explanation : Claude Bernand was a French Physiologist who first discovered about "homeostasis" which is defined as the controlled stability of the internal milieu, or internal environment, of cells and tissues in plants.

In plants stomatal opening and closing was done for maintaining homeostasis with the external and internal plant environment.

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3 years ago
GIVING 25 POINTS PLUS BRAINLIEST FOR CORRECT ANSWERS!!!!
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Answer:

The answer to your question is:

Explanation:

e) 9.10 x 10³ + 2.2 x 10⁶ = 2.2091 x 10⁶

f) 1113.0 - 14.6 x 10² = -347 = -3.47 x 10²

g) 6.18 x 10⁻⁴⁵ + 4.72 x 10⁻⁴⁴ = 5.338 x 10⁻⁴⁴

h) 4.25 x 10⁻³ - 1.6 x 10⁻² = -0.01175 = -1.175 x 10 ⁻²

5.- Calculate ...

a) 2.63 x 10⁻⁴

b) 2.26 x 10¹³

c) 1.97 x 10²

d) 1.65 x 10⁻²³

e) 2.5 x 10⁻⁸³

f) 1.61 x 10¹⁴

g) 2 x 10⁷⁹

h) 2.37 x 10⁻⁷

7 0
3 years ago
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BaCl2(H2O)2 type of reaction
amid [387]

Answer:

2HCl + Ba(OH)2 = BaCl2 + 2H2O

Explanation:

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Who invented the light bulbs for Thomas Edison?
Troyanec [42]
The first practical incandescent light bulb<span>. </span>Edison<span> and his team of researchers in </span>Edison's<span> laboratory in Menlo Park, N.J., tested more than 3,000 designs for </span>bulbs<span> between 1878 and 1880. In November 1879, </span>Edison<span> filed a patent for an electric </span>lamp<span> with a carbon filament.</span>
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3 years ago
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As a part of a clinical study, a pharmacist is asked to prepare a modification of a standard 22g package of a 2% mupirocin ointm
Vesna [10]

Answer:

226.8 mg of mupirocin powder are required

Explanation:

Given that;

weight of standard pack = 22 g

mupirocin by weight = 2%

so weight of mupirocin = 2% × 22 = 2/100 × 22 = 0.44 g

so by adding the needed quantity of mupirocin powder to prepare a 3% w/w mupirocin ointment

mg of mupirocin powder are required = ?, lets rep this with x

Total weight of ointment = 22 + x g

Amount of mupirocin  = 0.44 + x g

percentage of mupirocin  in ointment is 3?

so

3/100 = 0.44 + x g / 22 + x g

3( 22 + x g ) = 100( 0.44 + x g )

66 + 3x g = 44 + 100x g

66 - 44 = 100x g - 3x g

97 x g = 22

x g = 22 / 97

x g = 0.2268 g

we know that; 1 gram = 1000 Milligram

so 0.2268 g = x mg

x mg = 0.2268 × 1000

x mg  = 226.8 mg

Therefore, 226.8 mg of mupirocin powder are required

8 0
3 years ago
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