Answer:
Probability that at least 490 do not result in birth defects = 0.1076
Step-by-step explanation:
Given - The proportion of U.S. births that result in a birth defect is approximately 1/33 according to the Centers for Disease Control and Prevention (CDC). A local hospital randomly selects five births and lets the random variable X count the number not resulting in a defect. Assume the births are independent.
To find - If 500 births were observed rather than only 5, what is the approximate probability that at least 490 do not result in birth defects
Proof -
Given that,
P(birth that result in a birth defect) = 1/33
P(birth that not result in a birth defect) = 1 - 1/33 = 32/33
Now,
Given that, n = 500
X = Number of birth that does not result in birth defects
Now,
P(X ≥ 490) =
=
+ .......+
= 0.04541 + ......+0.0000002079
= 0.1076
⇒Probability that at least 490 do not result in birth defects = 0.1076
Answer:2
x
+
3
y
=
6
Step-by-step explanation:
in standard form
A1 is the 1st term
r is the difference, they can say "r" or "d" for the difference
1st a1 is the first term = -3
2nd "r" is the difference between each consecutive terms (coming after each other) = 1.5
the rule to get any term of the sequence as we add 1.5 each time is --> a1+(n-1)*d
a1 --> 1st term , n --> order of the term u want whether 2nd, 3rd , 25th
d --> difference
so to get the 2nd--> -3+(2-1)*1.5= -1.5
to get the 3rd --> -3 +(3-1)*1.5 = 0
<span>and so on </span>
The average speed is 4 miles per minute
WORK:
8mi=2minutes
÷2 ÷2
------------
4 1
4mi=1 minute
Answer:
Step-by-step explanation:
C