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3 years ago

An element that reacts with oxygen to form XO2 compounds and with chlorine to form XCI4 compounds???

Chemistry

1 answer:

yKpoI14uk [10]3 years ago

4 0

Answer:

An element X reacts with oxygen to form XO

and with chlorine to form XCl

. XO

is a white solid that melts at high temperatures (above 1000 degrees C). Under usual conditions, XCl

is a colorless liquid with a boiling point of 58 degrees C.

Explanation:

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PLEASE HELP!

Andrei [34K]

We will first calculate the concentration of sodium hydroxide, knowing the massive K hp. That was required to neutralize the 22.65 ml of sodium hydroxide solution. So the polarity sodium hydroxide will be take the massive K HP divided by its molar mass to get moles K HP. Then recognize one mol K HP reacted with one mole sodium hydroxide. Now we have mold sodium hydroxide to get concentration. We simply multiply by the leader volume of the sodium hydroxide solution. 22.65 ml is .02265 L. And we get a polarity of zero 0.3351 Molar sodium hydroxide. Now to calculate the concentration of hcl, we need to know the molds hcl divided by the volume of the hcl solution. To get the moles. Hcl will take the 25 ml of sodium hydroxide used in the tight rations converted to leaders. 25 ml is .02500 l multiply that by the concentration of sodium hydroxide that we just determined up here to get mold sodium hydroxide, then convert moles sodium hydroxide into molds. Hcl, recognizing it's a 1 to 1 molar relationship. Now that we have moles hcl, we just divide by the leaders of the hcl solution that was titrate, id 0.2. Sorry, 23.35 mL is 0.2335 liters. And we get a concentration of 0.3588 molar hcl. I hope that helps

7 0

2 years ago

In the reduction of 4-tert-butylcyclohexanone with sodium borohydride, the major product has the tert-butyl group in the equator

Evgen [1.6K]

Answer:

Axial position

Explanation:

In the reduction of 4-tert-butylcyclohexanone with sodium borohydride, the major product has the tert-butyl group in the equatorial position and the alcohol in the axial position.

The reason for this is that, axial bonds are parallel to each other. If substituents are larger than hydrogen, they experience a greater steric crowding in axial compared to the equatorial position. Therefore, many substituted cyclohexane compounds prefer a conformation in which the larger substituents are in equatorial position.

8 0

3 years ago

Calcula la densidad de un cuerpo que tiene la masa de 12g y un volumen de 3cm^3 dar el resultado en unidades del SI

kvv77 [185]

The density is 4 g/cm³ or 4000 kg/m³.

Density = mass/volume = 12 g/3 cm³ = 4 g/cm³

The measurement of 4 g/cm³ is already in <em>SI units</em>.

In SI <em>bas</em>e units,

Density = (4 g/1 cm³) × (1 kg/1000 g) × (100 cm/1 m)³ = 4000 kg/m³

3 0

3 years ago

How many orbitals are in 6s sublevel

Alla [95]

Each sublevel can have 6 electrons , basically 2 s orbital electrons 6 p orbitals electrons 14 f orbital electrons

Hope this helps.. if not sorry

4 0

3 years ago

0.6 sample an unknown organic acid found in muscle cells is burned in air and found to contain 0.24g of carbon, 0.04g of hydroge

prohojiy [21]

Answer:

Molecular formula is, C₃H₆O₃

Empirical formula (with the lowest subscript) → CH₂O

Explanation:

We assume that the organic acid's mass is 0.6 g. We know that, in 0.6 g of compound we have 0.24 g of C and 0.04 g of H, then, we have

(0.6 - 0.24 - 0.04) = 0.32 g of O.

We determine each mol:

0.24 g /12 g/mol = 0.02 mol of C

0.04 g/ 1g/mol = 0.04 mol of H

0.32 g/ 16 g/mol = 0.02 mol of O

1 mol of acid weighs 90 g/mol.

In 0.6 g of acid, we have, (0.6 g / 90g/mol) = 0.0067 moles

Let's find out the formula with rules of three:

0.00667 mol of acid have 0.02 moles of C

1 mol of acid may have (0.02 /0.00667) = 3 mol of C

0.00667 mol of acid have 0.04 moles of H

1 mol of acid may have (0.04 /0.00667) = 6 mol of H

0.00667 mol of acid have 0.02 moles of O

1 mol of acid may have (0.02 /0.00667) = 3 mol of O

Molecular formula is, C₃H₆O₃

We confirm by the molar mass: 12g/mol . 3 + 6 . 1g/mol + 32g/mol . 3 = 90

Empirical formula (with the lowest subscript) → CH₂O

5 0

3 years ago