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dangina [55]
3 years ago
13

Express 1123 pg in nanograms.

Chemistry
1 answer:
Strike441 [17]3 years ago
5 0
1.123 nano-grams is your answer, do you understand now gimme dat 5 star and brainiest

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What is produced when a strong acid reacts with the bicarbonate buffer system in the human body?
Norma-Jean [14]
Carbonic acid is produced when a strong acid reacts with the bicarbonate buffer system in the human body.
7 0
3 years ago
Read 2 more answers
Which property determines whether an acid is weak or strong?
julsineya [31]

Answer:

The property that determines whether an acid is weak or strong is its ability to dissociate and form ions.

Explanation:

8 0
3 years ago
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A compound has a molar mass of 90. grams per mole and the empirical formula CH2O. What is the molecular formula of this compound
k0ka [10]

Answer:

C₃H₆O₃

Explanation:

Data:

EF = CH₂O

MM = 90. g/mol

Calculations:

EF Mass = (12.01 + 2.016  + 16.00) u  = 30.03 u

The molecular formula is an integral multiple of the empirical formula.

MF = (EF)ₙ

n = \dfrac{\text{MF Mass}}{\text{EF Mass }} = \dfrac{\text{90. u}}{\text{30.03 u}} = 3.00  \approx 3

MF = (CH₂O)₃ = C₃H₆O₃

7 0
3 years ago
How many milliliters of 0.0630 m edta are required to react with 50.0 ml of 0.0110 m cu2 ?
gizmo_the_mogwai [7]
Moles Cu+2 = M * V
                     =  0.05 L * 0.011  m
                     = 0.00055 moles

when the molar ratio of Cu2+: EDTA = 1:1 so moles od EDTa also =0.00055 moles

and when the Molarity of EDTa = 0.0630 M

∴ Volume of EDTA =  moles / Molarity
                 = 0.00055 / 0.0630
                 = 0.0087 L = 8.7 L
4 0
3 years ago
How many moles of argon, Ar, are in 1.31×1024 Ar atoms?
ddd [48]

Answer:

2.18 mol Ar.

Explanation:

Hello there!

In this case, according to the definition of mole as the amount of particles of a given substance, it is possible to introduce the Avogadro's number to assert that 1 mole of any element contains 6.022x10²³ atoms; thus, the moles of Ar in the given amount of atoms turns out to be:

1.31x10^{24}Ar atoms*\frac{1molAr}{6.022x10^{23}atoms}\\\\=2.18molAr

Best regards!

5 0
3 years ago
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