Ask question

Ask question

All categories

3 years ago

13

Express 1123 pg in nanograms.

1 answer:

Strike441 [17]3 years ago

5 0

1.123 nano-grams is your answer, do you understand now gimme dat 5 star and brainiest

You might be interested in

The way in which light moves through objects is related to the type of material from which the object is made

adelina 88 [10]

Answer: True

Explanation:

The speed of light in a material medium depends on its molecular structure, in particular its electromagnetic properties, electrical and magnetic permeability. These properties may have different values for different wavelengths or frequencies of the incident light.

In this way,<u> the speed of light depends on the medium and reaches its maximum value in a vacuum</u>, so that, it will be lower in a material medium . In the vacuum (or in the air) the speed of light is 3 x 10⁸ m / s and in any other medium its value is lower.

<u>To characterize the particularities of the propagation of light in the media</u>, the refractive index is introduced ,

n = c / v

where c is <u>speed of light in a vacuum</u> and v is t<u>he speed of light in the medium</u> considered . So the speed of light in a medium is given by the refractive index whose value is always greater than 1.

6 0

4 years ago

What is the mass of 2.15 liters of N2 gas at STP?

ivann1987 [24]

Explanation:

mole number =mass/molar mass

mass=mole number × molar mass

mass= (volume of gas/volume at stp)molar mass

mass=(2.15/22.4)28

mass=2.69g

pls give brainliest

6 0

3 years ago

Will Rb and I form an iconic or covalent bond?

sergeinik [125]

Answer:

Most compounds of Rubidium are formed by ionic bonds.

Explanation:

8 0

3 years ago

The combustion of ethyne, shown below unbalance, produces heat which can be used to weld metals:

Andreyy89

Answer:

3.69 g

Explanation:

Given that:

The mass m = 325 g

The change in temperature ΔT = ( 1540 - 165)° C

= 1375 ° C

Heat capacity $c_p$ = 0.490 J/g°C

The amount of heat required:

q = mcΔT

q = 325 × 0.490 × 1375

q = 218968.75 J

q = 218.97 kJ

The equation for the reaction is expressed as:

$C_2H_{2(g)} + 5O_{2(g)} \to 2CO_{2(g)} + H_2O_{(g)} \ \ \ \ \ \Delta H^o_{reaction} = -1544 \ kJ$

Then,

1 mole of the ethyne is equal to 26 g of ethyne required for 1544 kJ heat.

Thus, for 218.97 kJ, the amount of ethyne gas required will be:

$= \dfrac{26 \ g}{1544 \ kJ} \times 218.97 \ kJ$

= 3.69 g

3 0

3 years ago

A laboratory analysis of a 100 g sample finds it is composed of 1.8 g hydrogen, 56.1 g sulfur, and 42.1 g oxygen. What is its em

Neporo4naja [7]

Answer: The empirical formula is $H_2S_2O_3$

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mas of H = 1.8 g

Mass of S = 56.1 g

Mass of O = 42.1 g

Step 1 : convert given masses into moles.

Moles of H = $\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{1.8g}{1g/mole}=1.8moles$

Mass of S = $\frac{\text{ given mass of S}}{\text{ molar mass of S}}= \frac{56.1g}{32g/mole}=1.8moles$

Moles of O= $\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{42.1g}{16g/mole}=2.6moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For H = $\frac{1.8}{1.8}=1$

For S = $\frac{1.8}{1.8}=1$

For O = $\frac{2.6}{1.8}=1.5$

Converting to whole number ratios

The ratio of H: S: O= 2: 2: 3

Hence the empirical formula is $H_2S_2O_3$

7 0

3 years ago