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Pepsi [2]
4 years ago
12

Can someone's help me with this

Chemistry
1 answer:
labwork [276]4 years ago
7 0
Oh ok just wait a minute
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Write the appropriate symbol for each of the following isotopes: (a) Z 11, A 23; (b) Z= 28, A= 64; (c) Z= 50, A =115; (d) Z= 20,
prohojiy [21]

Explanation:  

Z = atomic mass of the element and  , A = atomic mass of the element .

a) Z = 11, A =  23

Element = Sodium

  symbol: ²³₁₁Na  .

b) Z = 28, A =  64

Element = Nickel

  symbol: ⁶⁴₂₈Ni  .

c) Z = 50, A = 115

Element = tin

  symbol: ¹¹⁵₅₀Sn  .

d) Z = 20, A = 42

Element = Calcium

  symbol: ⁴²₂₀Ca .

6 0
3 years ago
Read 2 more answers
The equation represents the combustion of sucrose. C12H22O11 + 12O2 12CO2 + 11H2O If there are 10.0 g of sucrose and 8.0 g of ox
Vaselesa [24]
<span>0.0292 moles of sucrose are available. First, lookup the atomic weights of all involved elements Atomic weight Carbon = 12.0107 Atomic weight Hydrogen = 1.00794 Atomic weight Oxygen = 15.999 Now calculate the molar mass of sucrose 12 * 12.0107 + 22 * 1.00794 + 11 * 15.999 = 342.29208 g/mol Divide the mass of sucrose by its molar mass 10.0 g / 342.29208 g/mol = 0.029214816 mol Finally, round the result to 3 significant figures, giving 0.0292 moles</span>
7 0
3 years ago
Which property determines whether an acid is weak or strong?
julsineya [31]

Answer:

The property that determines whether an acid is weak or strong is its ability to dissociate and form ions.

Explanation:

8 0
3 years ago
Read 2 more answers
What is the half-life of A? What will the pressure, initially 32.1 kPa, at
kodGreya [7K]

Answer:

a) 32.09 kPa

b) 32.09 kPa

Explanation:

Given data:

rate constant = 3.56\times 10^{-7} s^{-1}

initial pressure is = 32.1 kPa

half life of A is calculated as

t_{1/2} = \frac{ln 2}{k}

t_{1/2} = \frac{ln 2}{3.56\time 10^{-7}}

t_{1/2} = = 1.956 \times 10^6 s

for calculating pressure we have follwing expression

ln p = ln P_o - kt

P =P_o e^{-kt}

a) P = 32.1 e^{-3.56\times 10^{-7} \times 10} = 32.09 kPa

b) P = 32.1 e^{-3.56\times 10^{-7} \times 10\times 60} = 32.09 kPa

5 0
3 years ago
Considering the activity series given below for metals and nonmetals, which reaction will occur?
Levart [38]

Answer:

Given the activity series of elements, the reaction that will occur is: 2AgNO3 + Ni -----> Ni(NO3)2 + 2Ag

3 0
2 years ago
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