basically have to find the lowest common multiply of 6 and 9.
The LCM of 6 minutes and 9 minutes = 18 minutes
so if they both leave at 4:00 p.m., they would then both leave at 4:18 p.m.
D=(b^2)-(4)(a)(c)
36-(4)(-2)(13)= 139
Answer:
- <u>They can catch up with the bus at 10:40 am.</u>
Explanation:
1. Set the time when Liana and her mother can leave (8:40 am) as t₀ = 0; thus the time of driving for them will be t.
2. The average speed at whic Liana's mother drive: 60 miles/hour
3. Thus, the distance they will have driven will be:
- distance = average speed × time = 60t
4. The time the bus left was 8:00 am, which is 40 minutes before Liana and her mom can leave.
Thus, the time wil have driven when Liana and her mom have driven t hours minutes will be: t + 40 min / 60 min/ hour = t + 2/3
5. The average speed of teh bus is 45 miles / hour
6. The distance the bus will have driven will be:
- distance = average speed × time = 45(t + 2/3)
7. When Liana and her mother catch up with the bus, the distances driven by both of them are equal:
Thus, Liana and her mom can catch up with the bus after 2 hours, since 8:40 am; this is, 10:40 am.
Answer:
(y^2-u^2)/2a = d
Step-by-step explanation:
We will move u^2 on left side and divide everything by 2a
