True! because if you have more than one variable, you aren’t going to know which variable changed the dependent variable.
Answer:
This process would be the one truly responsible for the "evolution" of mitochondria and chloroplasts as we know them from their prokaryotic ancestors. The cell process that would have initiated endosymbiosis is endocytosis; the process of taking things inside the cell
Answer:
<h2>Holaaaa !!</h2>
Explanation:
- at equilibrium , half of the 'O' molecules will diffuse in Next chamber while half of the 'Dark O' molecules will diffuse in First chamber.
- ∆ can not move in either medium across Membrane.
- 2 ∆ molecules can not move across the membrane due to its size.
Best Of Luck Sweetness !! Do well Baby !! ❤️
“Two species of crickets, Gryllus rubens and
Gryllus texensis, have different courtship songs which can be identified only
by the opposite sex of their own species” is an example of behavioral isolation.
Behavioral
isolation is an
important evolutionary mechanism that helps members of the same species
identify each other as proper mates.
The correct answer between all
the choices given is the third choice or letter C. I am hoping that this answer
has satisfied your query and it will be able to help you in your endeavor, and
if you would like, feel free to ask another question.
Answer:
The functional groups that define the two different ends of a single strand of nucleic acids are:
B. a free hydroxyl group on the 5' carbon a free hydroxyl group on the 3' carbon
G. a free phosphate group on the 5' carbon
Explanation:
A nucleic acid is a polymer formed of nucleotides that are linked with a phosphodiester bond. The structure of a nucleotide consists on a phosphate group linked to a pentose (ribose in RNA and deoxyribose in DNA) that is also attached to a nitrogenous base. The nitrogenous bases are adenine, guanine, cytosine, thymine (in DNA) and uracil (in RNA).
DNA and RNA are nucleic acids which can be found in a double or single strand presentation.
Nucleic acids are synthesize in the 5’ to 3’ direction, so that is why the convention is that the sequences are written and read in that direction.
The strand of a nucleic acid is directional with an end-to-end orientation, where the 5’ end has a free hydroxyl or phosphate group on the 5' carbon of the terminal pentose, and the 3’ end has a free hydroxyl group on the 3’ carbon on the terminal pentose (ribose/ deoxyribose).
