Question

The gravitational force of attraction between two students sitting at their desks in physics class is 3.9 × 10−8 N. If one student has a mass of 56.5 kg and the other has a mass of 61.5 kg, how far apart are the students sitting? The universal gravitational constant is 6.673 × 10−11 N · m2 /kg2 . Answer in units of m.

Answer 1

Answer:

Distance between the students is 2.4377 m

Explanation:

We have given that force between the students $F=3.9\times 10^{-8}N$

Mass of first student $m_1=56.5kg$

Mass of second student $m_2=61.5kg$

Gravitational constant $G=6.67\times 10^{-11}Nm^2/kg^2$

From gravitational law we know that force between two objects is given by

$F=\frac{Gm_1m_2}{R^2}$

So $3.9\times 10^{-8}=\frac{6.67\times 10^{-11}\times 56.5\times 61.5}{R^2}$

$R=2.4377m$

So distance between the students is 2.4377 m