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damaskus [11]
2 years ago
5

A car has a force of 2000N and a mass of 1000kg. What is the acceleration

Physics
1 answer:
Anastaziya [24]2 years ago
6 0

Answer:

2m/s/s

Explanation:

The formula goes- F=MA

F-Force M-Mass & A-Acceleration

We need to rearrange this formula to find the acceleration-

A=F/M

All we need to do now is substitute the values in

A=2000N/1000kg

A=2m/s^2

In the given option the last option (2m/s/s) would be the ans, as it's the same as 2m/s^2

So ya, I guess that's all

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A conducting loop has an area of 0.065 m2 and is positioned such that a uniform magnetic field is perpendicular to the plane of
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initial magnetic field  1.306 T

Explanation:

We have given area of the conducting loop A=0.065m^2

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We know that induced emf is given by e=\frac{d\Phi }{dt}=-A\frac{db}{dt}

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An engineering team has come to the stage in the engineering design
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Consider a vortex filament of strength Γ in the shape of a closed circular loop of radius R. Consider also a straight line throu
Sedbober [7]

Answer:

\vec{V} = \frac{\Gamma}{2R}\vec{A}

Explanation:

We define our values according to the text,

R= Radius

\vec{V} =Velocity

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From this and in a vectorial way we express an elemental lenght of this filmaent as \vec{dl}. So,

\vec{dl}x\vec{r} = R*dl*\vec{A}

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Applying Biot-Savart law, we have,

\vec{V} =\frac{\Gamma}{4\pi}\int\frac{\vec{dl}x\vec{r}}{r^3}

Substituting the preoviusly equation obtained,

\vec{V} = \frac{\Gamma}{4\pi}\int\frac{R*dl*\vec{A}}{R^3}

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\vec{V} = \frac{\Gamma(2\pi R \vec{A})}{4\pi R^2}

So we can express the velocity induced is,

\vec{V} = \frac{\Gamma}{2R}\vec{A}

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