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2 years ago

Help.. mee.. ;-; Dont answer if you dont know I dont want to fail this

Physics

2 answers:

timama [110]2 years ago

5 0

Answer:

It would be B because the warm air heats up and then burns the marshmallow. And the heat and the marshmallow were touching each other

Explanation:

Arte-miy333 [17]2 years ago

3 0

Answer:

its B because both objects are touching, every other option the heat moves through the air

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Should i beat up my sibling cause they mean to me?

Vlada [557]

no thats messed up lol

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3 years ago

Santa doesn't want to push a 25.0 kg wooden box across a wooden floor with a uk of 0.20 at

scZoUnD [109]

Answer:

49 N

Explanation:

In order to move the box at constant speed, the acceleration of the box must be zero (a=0): this means, according to Newton's second law,

F = ma

that the net force acting on the box, F, must be zero as well.

Here there are two forces acting on the box in the horizontal direction while it is moving:

- The force of push applied by the guy, F

- The frictional force, $F_f$

For an object moving on a flat surface, the frictional force is given by

$F_f = \mu_k mg$

where

$\mu_k$ is the coefficient of friction

m is the mass of the box

g is the acceleration of gravity

So the equation of the forces becomes

$F-\mu_k mg = 0$

And substituting:

$\mu_k = 0.20\\m = 25.0 kg\\g = 9.8 m/s^2$

We find the force that must be applied by the guy:

$F=\mu_k mg = (0.20)(25.0)(9.8)=49 N$

6 0

3 years ago

If a 1,000-kg car is traveling at 20.0 m/s when it reaches the bottom of a circular hill of radius 8.00 m, what normal force doe

scoray [572]

Answer:

i don't know this one.

Explanation:

6 0

3 years ago

NEED IN 5 MINUTES

Dmitrij [34]

sorry i didnt get this intime.....i hope you did well in whatever you did

Explanation:

7 0

3 years ago

Read 2 more answers

Two red blood cells each have a mass of 9.05×10−14 kg and carry a negative charge spread uniformly over their surfaces. The repu

belka [17]

Answer:

v = 330.7 m/s

Explanation:

Let say initially the speed of two blood cells is v and they are far apart from each other

when they come to the closest distance to each other then in that case the initial total kinetic energy of two blood cells will convert into electrostatic potential energy of the cells

So we can say

$\frac{1}{2}mv^2 + \frac{1}{2}mv^2 = \frac{kq_1q_2}{2r}$

here we know that

$m = 9.05 \times 10^{-14} kg$

$q_1 = -2.50 pC$

$q_2 = -3.30 pC$

$r = 3.75 \times 10^{-6} m$

now we will have

$(9.05 \times 10^{-14})v^2 = \frac{(9 \times 10^9)(2.50 \times 10^{-12})(3.30 \times 10^{-12})}{2(3.75 \times 10^{-6})}$

$v^2 = 1.09 \times 10^5$

$v = 330.7 m/s$

5 0

3 years ago