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4 years ago

How does comets differ from a asteroids

Physics

1 answer:

Temka [501]4 years ago

8 0

Comets are made of icy material and asteroids are rocky bodies and are denser than. Hope this helps.

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A harmonic wave on a string with a mass per unit length of 0.050 kg/m and a tension of 60 N has an amplitude of 5.0 cm. Each sec

Dennis_Churaev [7]

Answer:

Power of the string wave will be equal to 5.464 watt

Explanation:

We have given mass per unit length is 0.050 kg/m

Tension in the string T = 60 N

Amplitude of the wave A = 5 cm = 0.05 m

Frequency f = 8 Hz

So angular frequency $\omega =2\pi f=2\times 3.14\times 8=50.24rad/sec$

Velocity of the string wave is equal to $v=\sqrt{\frac{T}{\mu }}=\sqrt{\frac{60}{0.050}}=34.641m/sec$

Power of wave propagation is equal to $P=\frac{1}{2}\mu \omega ^2vA^2=\frac{1}{2}\times 0.050\times 50.24^2\times 34.641\times 0.05^2=5.464watt$

So power of the wave will be equal to 5.464 watt

6 0

3 years ago

A car has an acceleration of -5 m/s^2. Describe the car’s motion

AlladinOne [14]

Explanation:

because the acceleration is negative, this indicates a deceleration (or slowing down) . Hence we can say that:

The car is decelerating (slowing down), i.e its velocity is decreasing, at a constant rate of 5m/s².

7 0

4 years ago

If the white car experiences a change in momentum equal to 105,000 kg*m/s and is in contact with the red car for 5 seconds befor

larisa86 [58]

Answer:

21000 N

Explanation:

From the question given above, the following data were obtained:

Change in momentum = 105000 kg.m/s

Time = 5s

Force =?

Force is related to momentum and time according to the following formula:

Force = Change in momentum / time

With the above formula, we can calculate the force the white car experience during the collision. This can be obtained as illustrated below:

Change in momentum = 105000 kg.m/s

Time = 5s

Force =?

Force = Change in momentum / time

Force = 105000 / 5

Force = 21000 N

Thus, the white car experience a force of 21000 N during the collision.

4 0

3 years ago

6. A skier starts from rest at the top of a frictionless incline of height 20.0 m. At

n200080 [17]

Explanation:

a. KE at bottom = PE at top

½ mv² = mgh

v = √(2gh)

v = √(2 × 9.8 m/s² × 20.0 m)

v = 19.8 m/s

b. Work by friction = PE at top

mgμ d = mgh

d = h / μ

d = 20.0 m / 0.210

d = 95.2 m

6 0

3 years ago

A 2.5g copper penny is given a charge of -4.0*10^-9c. how mny excess electrons are on the penny?

Lyrx [107]

Answer : The excess of electrons on the penny are, $2.5\times 10^{10}$ electrons

Solution : Given,

Total charge = $-4.0\times 10^{-9}C$

Charge on electron = $-1.6\times 10^{-19}C$

Formula used :

$\text{Excess of electrons}=\frac{\text{Total charge}}{\text{Charge of electron}}$

Now put all the given values in this formula, we get the excess of electrons present on the penny.

$\text{Excess of electrons}=\frac{\text{Total charge}}{\text{Charge of electron}}=\frac{-4.0\times 10^{-9}C}{-1.6\times 10^{-19}C/e^-}=2.5\times 10^{10}e^-$

Therefore, the excess of electrons on the penny are, $2.5\times 10^{10}$ electrons

7 0

3 years ago