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Lubov Fominskaja [6]
3 years ago
8

Alejandro Kirk is the catcher for the Blue Jays’ baseball team. He exerts a forward force on the 0.145-kg baseball to bring it t

o rest from a speed of 38.2 m/s. During the process, his hand recoils a distance of 0.135 m.
Determine is the acceleration of the ball.
Determine the force applied by Alejandro.
Physics
1 answer:
lozanna [386]3 years ago
7 0

The kinematics and Newton's second law allow to find the results for the questions about the motion of the ball are:

  • The acceleration is: a = 5.4 10³ m / s²
  • The force is: F = 7.84 10² N

Given parameters

  • Mass of the ball m = 0.145 kg
  • Ball starts speed vo = 38.2 m / s
  • Setback distance x = 0.135 m

To find

  • Acceleration
  • The force

Kinematics studies the movement of bodies, looking for relationships between the position, speed and acceleration of bodies.

         v² = v₀² - 2 ax

Wher vo es la initial veloicity, a the acceleration y x is the distance,

When the ball stops the velocity is zero.

         0 = v₀² - 2ax

         a = \frac{v_o^2}{2x}  

Let's calculate

         a = \frac{38.2^2}{2 \ 0.135}  

         a = 5.4 10³ m / s²

Newton's second law establishes a relationship between force, mass, and acceleration of the body.

             F = ma

             F = 0.145 5.4 10³

             F = 7.84 10² N

In conclusion using kinematics and Newton's second law we can find the results for the questions about the motion of the ball are:

  • The acceleration is: a = 5.4 10³ m / s²
  • The force is: F = 7.84 10² N

Learn more here: brainly.com/question/13536532

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Answer:

0.42 meters/second

Explanation:

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We want the speed in meters/second, so we have to convert the 10 minutes elapsed during the trip into seconds. Then we need a conversion factor, 1 minute is equivalent to 60 seconds.

time = 10 minutes * (60 seconds/1 minute) = 600 seconds (notice that minute is cancelled because is multiplying and dividing)

Now, we can compute the average speed is as follows:

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4 years ago
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guapka [62]

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7 0
3 years ago
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Titanium is a metal used to make golf clubs. A rectangular bar of this metal measuring 1.96 cm x 2.19 cm x 2.63 cm was found to
masha68 [24]

4.012\frac{gr}{cm^3}

Explanation

the density of an object is given by:

\text{Density(d)}=\frac{mass(m)}{\text{volume(v)}}

Step 1

find the volume of the bar

a)find the volume of the rectangular bar.

the volume of a rectangular prism is given by:

\text{Volume}=\text{ length}\cdot widht\cdot depth

replace

\begin{gathered} \text{Volume}=(\text{ 2.63}\cdot2.19\cdot1.96)(cm^3) \\ \text{Volume}=11.289012(cm^3) \end{gathered}

Step 2

now,

Let

\begin{gathered} \text{Volume}=11.289012(cm^3) \\ \text{mass}=\text{ 45.3 gr} \end{gathered}

replace in the formula

\begin{gathered} \text{Density(d)}=\frac{mass(m)}{\text{volume(v)}} \\ d=\frac{45.3\text{ gr}}{11.289012(cm^3)} \\ d=4.012\frac{gr}{cm^3} \end{gathered}

therefore, the answer is

4.012\frac{gr}{cm^3}

I hope this helps you

4 0
2 years ago
A 0.086 kg bullet is fired at 266 m/s and collides with a 6.3 kg wooden block that is initially stationary. The bullet embeds in
olga2289 [7]

Answer:

The value of speed of wooden block at the instant after the collision   V_f = 262.41  \frac{m}{s}

Explanation:

Given data

Mass of block = 6.3 kg

Mass of bullet = 0.086 kg

Velocity of bullet V_0 = 266 \frac{m}{s}

Final velocity of whole system is

V_f = M_{b}\frac{ V_0}{M_b + (M_{block})}

Put all the values in above formula we get

V_f = \frac{(6.3)(266)}{(6.3 + 0.086)}

V_f = 262.41  \frac{m}{s}

This is the value of speed of wooden block at the instant after the collision.

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