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PilotLPTM [1.2K]
3 years ago
5

To form a better telescope, you can interchange eyepieces for new focal lengths. A new design lets you replace both lenses, whic

h new configuration would make a more powerful telescope?
a. a short focal length objective and a short focal length eyepiece.
b. a long focal length objective and a short focal length eyepiece.
c. a long focal length objective and a long focal length eyepiece.
d. a short focal length objective and a long focal length eyepiece.
Physics
1 answer:
HACTEHA [7]3 years ago
8 0

Answer:

option (b)

Explanation:

for a telescope, the object is placed very far from the objective lens so the focal length of objective is large and the eye piece is of short focal length.

So, long focal length objective and short focal length eyepiece.

Option (b) is correct.

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A block of mass 9.5kg rests on a slope an angle of 23.0∘ relative to the horizontal. What is the size of the contact force norma
Rudiy27

The Normal Force = M x G x Cos(theta)

= 9.5 Kg x 9.8 m/s^2 x cos 23

= 9.5 Kg x 9.8 m/s^2 x 0.9205

Converting Kg to Newton,

1 Kg  = 9.81 N

= 9.5 Kg x 9.81 N x 9.8 m/s^2 x 0.9205

= 840.702 N

6 0
3 years ago
A skateboarder travels on a horizontal surface with an initial velocity of 4.0 m/s toward the south and a constant acceleration
Alenkinab [10]

Answer:

a) 0.32 m b) -2.4 m c) 1.08 m/s d) -4 m/s

Explanation:

a)

  • As the x and y axes (as chosen) are perpendicular each other, the movements along these axes are independent each other.
  • This means that we can use the kinematic equations for displacements along both axes.
  • In the x direction, as the only initial velocity is in the south direction (-y axis), the skateboarder is at rest, so we can write:

        x =\frac{1}{2}*a*t^{2} (1)

  • In the y-direction, as no acceleration is acting on the skateboarder, we can write  the following displacement equation:

        y = v_{0y} * t  (2)

  • For t = 0.6s, replacing by the givens, we get the position (displacement from the origin) on the x-axis, as follows:

       x =\frac{1}{2}*a*t^{2} =\frac{1}{2} * 1.8 m/s2*(0.6s)^{2}\\ x = 0.32 m

b)

  • From (2) we can get the position on the y-axis (displacement from the origin) as follows:

        y = v_{0y} * t  =  -4 m/s * 0.6 s = -2.4 m

c)

  • In the x- direction, we can find the component of the velocity along this direction, as follows:

        v_{fx} = a*t

  • Replacing by the values, we have:

        v_{fx} = a*t = 1.8 m/s2 * 0.6 s = 1.08 m/s

d)

  • As the skateboarder moves along the y-axis at a constant speed equal to her initial velocity, we  have:

        vfy = voy = -4 m/s

8 0
4 years ago
If the particle is located slightly to the left of point B, its acceleration is __________.
Igoryamba

(1) directed to the right

Explanation:

To the right of B, u(x) is a decreasing function & so its derivative is negative,this implies that the x component of the force on a particle at this position is positive,or that the force is directed towards right .Small deviations from equilibrium at point B causes a force to accelerate the particle away ,hence particle is in <u>unstable equilibrium.</u>

7 0
4 years ago
If the range of the projectile is 4.3 m, the time-of-flight is T = 0.829 s, and air resistance is negligible, determine the foll
ankoles [38]

Answer

given,

range of the projectile = 4.3 m

time of flight = T = 0.829 s

v =\dfrac{d}{T}

v =\dfrac{4.3}{0.829}

     v = 5.19 m/s

vertical component of velocity of projectile

v_y = gt'

v_y = 9.8 \times {\dfrac{T}{2}}

v_y = 9.8 \times {\dfrac{0.829}{2}}

v_y =4.06\ m/s

a) Launch angle

 \theta = tan^{-1}(\dfrac{v_y}{v})

 \theta = tan^{-1}(\dfrac{4.06}{5.19})

    θ = 38°

b) initial speed of projectile

  v = \sqrt{v_x^2 + v_y^2}

  v = \sqrt{5.19^2 + 4.06^2}

         v = 6.59 m/s

c) maximum height reached by the projectile

     y_{max}=v_{avg}t'

     y_{max}=\dfrac{1}{2}v_y\dfrac{T}{2}

     y_{max}=\dfrac{1}{2}\times(g\dfrac{T}{2})\times\dfrac{T}{2}

     y_{max}=\dfrac{gT^2}{8}          

7 0
4 years ago
What is kinetic energy
aksik [14]

Answer:

Kinetic energy, form of energy that an object or a particle has by reason of its motion. ... Kinetic energy is a property of a moving object or particle and depends not only on its motion but also on its mass.

Credits to britannica.com

Explanation:

Hope this helps

4 0
3 years ago
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