The Normal Force = M x G x Cos(theta)
= 9.5 Kg x 9.8 m/s^2 x cos 23
= 9.5 Kg x 9.8 m/s^2 x 0.9205
Converting Kg to Newton,
1 Kg = 9.81 N
= 9.5 Kg x 9.81 N x 9.8 m/s^2 x 0.9205
= 840.702 N
Answer:
a) 0.32 m b) -2.4 m c) 1.08 m/s d) -4 m/s
Explanation:
a)
- As the x and y axes (as chosen) are perpendicular each other, the movements along these axes are independent each other.
- This means that we can use the kinematic equations for displacements along both axes.
- In the x direction, as the only initial velocity is in the south direction (-y axis), the skateboarder is at rest, so we can write:

- In the y-direction, as no acceleration is acting on the skateboarder, we can write the following displacement equation:

- For t = 0.6s, replacing by the givens, we get the position (displacement from the origin) on the x-axis, as follows:

b)
- From (2) we can get the position on the y-axis (displacement from the origin) as follows:

c)
- In the x- direction, we can find the component of the velocity along this direction, as follows:

- Replacing by the values, we have:

d)
- As the skateboarder moves along the y-axis at a constant speed equal to her initial velocity, we have:
vfy = voy = -4 m/s
(1) directed to the right
Explanation:
To the right of B, u(x) is a decreasing function & so its derivative is negative,this implies that the x component of the force on a particle at this position is positive,or that the force is directed towards right .Small deviations from equilibrium at point B causes a force to accelerate the particle away ,hence particle is in <u>unstable equilibrium.</u>
Answer
given,
range of the projectile = 4.3 m
time of flight = T = 0.829 s


v = 5.19 m/s
vertical component of velocity of projectile
v_y = gt'



a) Launch angle


θ = 38°
b) initial speed of projectile


v = 6.59 m/s
c) maximum height reached by the projectile



Answer:
Kinetic energy, form of energy that an object or a particle has by reason of its motion. ... Kinetic energy is a property of a moving object or particle and depends not only on its motion but also on its mass.
Credits to britannica.com
Explanation:
Hope this helps