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PilotLPTM [1.2K]
3 years ago
5

To form a better telescope, you can interchange eyepieces for new focal lengths. A new design lets you replace both lenses, whic

h new configuration would make a more powerful telescope?
a. a short focal length objective and a short focal length eyepiece.
b. a long focal length objective and a short focal length eyepiece.
c. a long focal length objective and a long focal length eyepiece.
d. a short focal length objective and a long focal length eyepiece.
Physics
1 answer:
HACTEHA [7]3 years ago
8 0

Answer:

option (b)

Explanation:

for a telescope, the object is placed very far from the objective lens so the focal length of objective is large and the eye piece is of short focal length.

So, long focal length objective and short focal length eyepiece.

Option (b) is correct.

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A box with a mass of 18 kg is pushed across the floor. It has coefficient of friction of 0.39. Calculate the force of friction i
Taya2010 [7]

Answer:

68.8 N

Explanation:

From the question given above, the following data were obtained:

Mass (m) of box = 18 Kg

Coefficient of friction (μ) = 0.39

Force of friction (F) =?

Next, we shall determine the normal force of the box. This is illustrated below:

Mass (m) of object = 18 Kg

Acceleration due to gravity (g) = 9.8 m/s²

Normal force (N) =?

N = mg

N = 18 × 9.8

N = 176.4 N

Finally, we shall determine the force of friction experienced by the object. This is illustrated below:

Coefficient of friction (μ) = 0.39

Normal force (N) = 176.4 N

Force of friction (F) =?

F = μN

F = 0.39 × 176.4

F = 68.796 ≈ 68.8 N

Thus, the box experience a frictional force of 68.8 N.

3 0
2 years ago
What happens to the current supplied by the battery when you add an identical bulb in parallel to the original bulb?
Marysya12 [62]

Answer:

b. The current stays the same.

Explanation:

In the case given current is supplied by the battery to a bulb . Here, we should know that bulb also apply resistance to the flow of current .

Now, when an identical bulb is connected in parallel to the original bulb .

Therefore, both the resistance( bulb) are in parallel.

We know, when two resistance are in parallel , current through them is same and voltage is divided between them.

Therefore, in this case current stays same in the original bulb.

Hence, this is the required solution.

6 0
3 years ago
A honeybee with a mass of 0.150 g lands on one end of a floating 4.75-g popsicle stick, as shown in (Figure 1) . After sitting a
Alekssandra [29.7K]

Answer:

0.0443 m/s

Explanation:

m_1 = Mass of honeybee = 0.15 g

m_2 = Mass of popsicle stick = 4.75 g

v_1 = Velocity of honeybee

v_2 = Velocity of stick = 0.14 cm/s

In this system the linear momentum is conserved

m_1v_1=m_2v_2\\\Rightarrow v_1=\dfrac{m_2v_2}{m_1}\\\Rightarrow v_1=\dfrac{4.75\times 0.14}{0.15}\\\Rightarrow v_1=4.43\ m/s

The velocity of the bee is 4.43 cm/s or 0.0443 m/s

5 0
3 years ago
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