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3 years ago

The nucleus of an atom consists of neutrons and electrons. tf

Physics

2 answers:

Maurinko [17]3 years ago

7 0

the answer is very much true

yKpoI14uk [10]3 years ago

3 0

True because the neutrons are inside of the nucleus and the electron revolve around the nucleus

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As your hand moves back and forth to generate longitudinal pulses in a spiral spring, your hand completes 2.91 back-and-forth cy

Lapatulllka [165]

Answer:

Wavelength, $\lambda=0.011\ m$

Explanation:

Given that,

Number of cycles in a spiral spring is 2.91 in every 3.67 s

The velocity of the pulse in the spring is 0.925 cm/s, v = 0.00925 m/s

To find,

Wavelength

Solution,

Number of cycles per unit time is called frequency of a wave. The frequency of the longitudinal pulse is,

$f=\dfrac{2.91}{3.67}=0.79\ Hz$

The wavelength of a wave is given by :

$\lambda=\dfrac{v}{f}$

$\lambda=\dfrac{0.00925\ m/s}{0.79\ Hz}$

$\lambda=0.011\ m$

So, the wavelength of the longitudinal pulse is 0.011 meters. Hence, this is the required solution.

8 0

2 years ago

The best scientific reason for a scientist to accept a specific theory is?

lions [1.4K]

Answer:

The theory is supported by all the available observations and data.

Explanation: The scientific community will accept a theory when a sufficient body of evidence supports it. This includes experiments that refute other potential theories. Experiments should also be carried out that attempt to disprove the theory but cannot.

It should not matter who proposed the theory or who supports it, and instead should entirely be based on the quality and abundance of data supporting it.

Hope this helps!

Pls Mark me brainliest

-ya girl Lizzie

7 0

2 years ago

Consider the following waves representing electromagnetic radiation: An illustration shows two waves representing electromagneti

Murljashka [212]

Answer:

a) red wave hs a longer wavelength than the green wave

b)f = 1.875 10¹¹ Hz , f_green = 5.45 10¹⁴Hz

c) E = 1.24 10⁻²² J , E_green = 3.6 10⁻¹⁹ J

d) The red wave is in the infrared range, heat waves

The green wave is in the visible wavelength

Explanation:

a) The green wave are on the left in the electromagnetic spectrum so the red wave has a longer wavelength than the green wave

The green wavelength is in the range of 550 10⁻⁹ m

The speed of the wave is

c = λ f

f = c /λ

b) The frequency of the red wave is

f = 3 10⁸ / 1.6 10⁻³

f = 1.875 10¹¹ Hz

For the green wave

f_green = 3 10⁸/550 10⁻⁹

f_green = 5.45 10¹⁴Hz

c) The photon energy is given by the Planck equation

E = h f

E = 6.63 10⁻³⁴ 1.875 10¹¹

E = 1.24 10⁻²² J

For the green wave

E_green = 6.63 10⁻³⁴ 5.45 10¹⁴

E_green = 3.6 10⁻¹⁹ J

d) The speed of electromagnetic waves is constant and has a value of 3 108 m / s

The red wave is in the infrared range, heat waves

The green wave is in the visible wavelength

6 0

3 years ago

A box full of charged plastic balls sits on a table. The electric force exerted on a ball near one upper corner of the box has c

tatuchka [14]

We have that the values for F north, F east, F up are

$F_N=1.09090909*10^{-5}$
$F_E=5.18181818*10^{-6}$
$F_E=2*10^{-6}$

From the Question we are told that

electric force $F_1 = 1.2 x 10^{-3} N(N)$

electric force , $F_2=5.7 x 10^{-4} N(E)$

electric force , $F_3=2.2 x 10^{-4} N (U)$

charge on this ball one $q_1= 110 nC.$

charge on this ball two $q_2= -50 nC.$

Generally the equation for the F north is mathematically given as

$F_N=\frac{F_1}{q_1}\\\\F_N=\frac{ 1.2 * 10^{-3} )}{110}$

$F_N=1.09090909*10^{-5}$

For F East

$F_E=\frac{F_2}{q_1}\\\\F_E=\frac{5.7 x 10^-4 }{110}$

$F_E=5.18181818*10^{-6}$

For F UP

$F_U=\frac{F_3}{q_1}\\\\F_U=\frac{2.2 x 10^-4 }{110}$

$F_E=2*10^{-6}$

For more information on this visit

brainly.com/question/21811998

5 0

2 years ago

A bat moving at 3.7 m/s is chasing a ying insect. The bat emits a 36 kHz chirp and receives back an echo at 36.79 kHz. At what s

3241004551 [841]

Answer:

The speed the bat is gaining on its prey is 0.03m/s

Explanation:

Given;

speed of the bat, v₀ = 3.7 m/s

frequency of the bat, F₀ = 36 kHz

frequency of the source, Fs = 36.79

This is relative motion between a source of the sound and the observer. The phenomenon is known as Doppler effect.

Apply the following equation to determine the speed of the insect which is the source;

$F_0 = F_s[\frac{v+v_0}{v-v_s} ]\\\\\frac{F_0}{F_s} = [\frac{v+v_0}{v-v_s} ]\\\\\frac{36.79}{36} = \frac{340+3.7}{340-v_s}\\\\1.0219 = \frac{343.7}{340-v_s}\\\\ 340-v_s = \frac{343.7}{1.0219}\\\\340-v_s = 336.33\\\\v_s = 340-336.33\\\\v_s = 3.67 \ m/s$

The speed the bat is gaining on its prey = 3.7m/s - 3.67m/s = 0.03 m/s

Therefore, the speed the bat is gaining on its prey is 0.03m/s

8 0

2 years ago