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3 years ago

2.Cars were previously manufactured to be as sturdy as possible, whereas today's cars

Physics

1 answer:

Marina CMI [18]3 years ago

4 0

Answer:

Crumple zones are designed to absorb and redistribute the force of a collision. ... Also known as a crush zone, crumple zones are areas of a vehicle that are designed to deform and crumple in a collision. This absorbs some of the energy of the impact, preventing it from being transmitted to the occupants.

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Is it accurate to say that galaxies take up most of the volume of space? Why or why not?

RUDIKE [14]

Answer:

ntergalactic space takes up most of the volume of the universe, but even galaxies and star systems consist almost entirely of empty space.

Explanation:

so to be exact galixes do make up most of the volume of space because galaxies are what make up space!

4 0

2 years ago

2. Different kinds of light are produced from waves of different ____________________.

gregori [183]

Answer: Either electromagnetic radiation or energy is the answer to your question.

4 0

3 years ago

What is the speed of an object that travels 20 meters in 4 seconds?

Iteru [2.4K]

Given:-

Distance covered by the particle (s) = 20 m
Time taken (t) = 4 seconds

To Find: Speed of it.

We know,

v = s/t

where,

v = Speed,
s = Distance &
t = Time taken.

Putting the values,

v = (20 m)/(4 s)

→ v = 5 m/s (Ans.)

5 0

3 years ago

Examples of buoyancy

Lana71 [14]

A ball would be something that floats in warter

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3 years ago

A box has a weight of 150 N and is being pulled across a horizontal floor by a force that has a magnitude of 110 N. The pulling

ivann1987 [24]

Answer:

42.99°

Explanation:

$F_h$ = Kinetic friction force

$F_{\theta}$ = Pulling force at angle $\theta$

$N_h$ = Weight of the box = 150 N

Kinetic friction force

$F_h=\muN_h$

Pulling force at angle $\theta$

$F_{\theta}=\muN_{\theta}$

N = Pulling force

According to question

$\frac{F_h}{F_{\theta}}=\frac{2}{1}\\\Rightarrow \frac{\muN_h}{\muN_{\theta}}=2\\\Rightarrow \frac{N_h}{N_{\theta}}=2\\\Rightarrow N_{\theta}=\frac{N_h}{2}\\\Rightarrow N_{\theta}=\frac{150}{2}\\\Rightarrow N_{\theta}=75\ N$

Applying Newton's second law in the vertical direction we get

$N_h-Nsin\theta=N_{\theta}\\\Rightarrow 150-110sin\theta=75\\\Rightarrow \theta=sin^{-1}\frac{75}{110}\\\Rightarrow \theta=42.99\ ^{\circ}$

The angle is 42.99°

8 0

3 years ago