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2 years ago

A pump is to lift 18 kg of water per minute tthrough a height of 3.6 m. what output rating (watts) should the pump have?

1 answer:

7 0

Given: Mass m = 18 Kg; Height h = 3.6 m; Time t = 60 s

Required: Power output in unit of Watts

Formula: P = mgh/t

P = (18 Kg)(9.8 m/s²)(3.6 m)/60 s

P = 10.58 J/s or Watts

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prc-2) A soccer ball accelerates from rest and rolls 6.5m down a hill for 3.1 seconds. It is then stopped by a tree. Find the fi

anastassius [24]

Answer:

15?6 and 17 plus 18 equals e b d f g so correct

Explanation:

yws you're welcome and thank for your help with this and I will be there is it ok if I get a and I can

7 0

3 years ago

A long solenoid, of radius a, is driven by an alternating current, so that the field inside is sinusoidal: B(t) B cos(ot)ż. A ci

Scrat [10]

Answer:

The current induced in the loop is $\dfrac{\pi a^2 B\omega}{4R}\ \sin(\omega t)$ .

Explanation:

Given that,

Magnetic field $B(t)=B\cos(\omega t)\ z$

Radius $r =\dfrac{a}{2}$

Resistance =R

We need to calculate the area of the loop

Using formula of area

$A = \pi r^2$

Put the value of r in to the formula

$A =\pi\times(\dfrac{a}{2})^2$

$A=\dfrac{\pi a^2}{4}$

We need to calculate the flux

Using formula of flux

$\phi=BA$

$\phi=B\cos(\omega t)\dfrac{\pi a^2}{2}$

We need to calculate the emf

Using formula of emf

$\epsilon=-\dfrac{d\phi}{dt}$

$\epsilon=-\dfrac{-\pi a^2B}{4}(-\omega\sin\omega t)$

$\epsilon=\dfrac{\pi a^2B\omega\sin(\omega t)}{4}$

We need to calculate the current

Using formula of current

$I(t)=\dfrac{\epsilon}{R}$

$I(t)=\dfrac{\dfrac{\pi a^2B\omega\sin(\omega t)}{4}}{R}$

$I(t)=\dfrac{\pi a^2 B\omega}{4R}\ \sin(\omega t)$

Hence, The current induced in the loop is $\dfrac{\pi a^2 B\omega}{4R}\ \sin(\omega t)$ .

4 0

3 years ago

Tom and his twin brother Tim have a combined mass of 200.0 kg and are

Dvinal [7]

Answer:

I don't know really I wish I could help

4 0

2 years ago

Two spherical inflated rubber balloons each have the same amount of charge spread uniformly on their surfaces. If the repelling

nataly862011 [7]

Answer:

$5.0\cdot 10^{-6}C$

Explanation:

The magnitude of the electrostatic force between two charged objects is given by Coulomb's law:

$F=k\frac{q_1 q_2}{r^2}$

where:

$k=8.99\cdot 10^9 Nm^{-2}C^{-2}$ is the Coulomb's constant

$q_1, q_2$ are the two charges on the two objects

r is the separation between the two charges

The force is:

- Repulsive if the two charges have same sign

- Attractive if the two charges have opposite sign

In this problem:

F = 2.5 N is the force between the two balloons

r = 0.30 m is their separation

$q_1=q_2=q$ is the charge on each balloon (they have the same charge)

So, re-arranging the equation, we can find the value of q:

$F=\frac{kq^2}{r^2}\\q=\sqrt{\frac{Fr^2}{k}}=\sqrt{\frac{(2.5)(0.30)^2}{8.99\cdot 10^9}}=5.0\cdot 10^{-6}C$

We are also told that the force between them is repulsive: this means that the charges on the two balloons have same sign (so, either they are both positive, or both negative).

4 0

3 years ago

A light-year is about: 6 million miles 6 million kilometers 6 billion miles 6 trillion miles

vazorg [7]

Answer: 6 trillion miles

Explanation: 1 light-year = 6 trillion miles

7 0

2 years ago