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SVEN [57.7K]
3 years ago
5

. What will happen if there is an oil spill in the Arctic Ocean based on the statements above? A) The Atlantic and Southern Ocea

ns are in danger form the spill. B) Only the Atlantic Ocean might suffer contamination from that spill. C) Ocean currents can carry the oil to various locations throughout the world. D) The Arctic Ocean is separated from the other four oceans so contamination would not occur.
Physics
2 answers:
Daniel [21]3 years ago
8 0

Answer:   a

Explanation:

ohaa [14]3 years ago
6 0

Answer: the answer is a.

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A ball is thrown straight up with an initial velocity of 6.4 m/s. It travels for 0.64 seconds, and has a change of position of 2
Naya [18.7K]

Answer:

V = 0.9 m/s

Explanation:

The parameters given are:

Initial velocity U = 6.4 m/s

Time t = 0.64s

Height h = 2.05 m

To find the final velocity, let us use third equation of motion

V^2 = U^2 - 2gH

Since the ball is going upward, g will be negative

Substitute all the parameters into the formula

V^2 = 6.4^2 - 2 × 9.8 × 2.05

V^2 = 40.96 - 40.18

V^2 = 0.78

V = sqrt( 0.78)

V = 0.883 m/ s

V = 0.9 m/ s approximately

6 0
3 years ago
BI
Charra [1.4K]

Answer: A

Explanation:

8 0
3 years ago
Which of the following is a contact force?
Nutka1998 [239]
The contact force is indeed caused by "Contact". 

Air resistance is basically a type of friction, which is apparently present providing two object contact.

The rest selections are all interaction force, which is not necessarily caused by contact.
4 0
3 years ago
Read 2 more answers
Which of the following represents an image that is located in front of a lens?
Lostsunrise [7]
-di represents an image in front of a lens
5 0
3 years ago
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A smooth circular hoop with a radius of 0.800 m is placed flat on the floor. A 0.300-kg particle slides around the inside edge o
Marrrta [24]

Answer:

a)11.25 J

b)Number of revolution = 1

Explanation:

Given that

Radius ,r= 0.8 m

m= 0.3 kg

Initial speed ,u= 10 m/s

final speed ,v= 5 m/s

a)

Initial energy

KE_i=\dfrac{1}{2}mu^2

KE_i=\dfrac{1}{2}0.3\times 10^2

KEi= 15 J

Final kinetic energy

KE_f=\dfrac{1}{2}mv^2

KE_f=\dfrac{1}{2}0.3\times 5^2

KEf=3.75 J

The  energy transformed from mechanical to internal = 15 - 3.75 J = 11.25 J

b)

The minimum value to complete the circular arc

 V=\sqrt{r.g}

Now by putting the values

V=\sqrt{0.8\times 10}

V= 2.82 m/s

So kinetic energy KE

KE=\dfrac{1}{2}mV^2

KE=\dfrac{1}{2}0.3\times 2.82^2

KE=1.19 J

ΔKE= KEi - KE

ΔKE= 15- 1.19 J

ΔKE=13.80 J

The minimum energy required to complete 2 revolutions = 2 x 11.25 J

                                                                                                    = 22.5 J

Here 22.5 J is greater than 13.8 J.So the particle will complete only one revolution.

Number of revolution = 1

4 0
3 years ago
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