The answer is A.
A positive charge’s electric field pushes out.
Hope this helps! -Avenging
Speed = frequency x wavelength
300,000,000 = 125000 x wavelength
wavelength = 125000/300,000,000 =4.16667x10^-4 meters
or 4.1667E-4 meters
Answer:
The potential difference between the plates is ![8.4\times10^{3}\ V](https://tex.z-dn.net/?f=8.4%5Ctimes10%5E%7B3%7D%5C%20V)
Explanation:
Given that,
Distance = 1.4 mm
Electric field strength ![E= 6.0\times10^{6}\ N/C](https://tex.z-dn.net/?f=E%3D%206.0%5Ctimes10%5E%7B6%7D%5C%20N%2FC)
Let the potential difference is V.
We need to calculate the potential difference between the plates
Using formula of electric field
![E=\dfrac{V}{d}](https://tex.z-dn.net/?f=E%3D%5Cdfrac%7BV%7D%7Bd%7D)
![V=Ed](https://tex.z-dn.net/?f=V%3DEd)
Where, V = potential
d = distance
Put the value into the formula
![V=6.0\times10^{6}\times1.4\times10^{-3}](https://tex.z-dn.net/?f=V%3D6.0%5Ctimes10%5E%7B6%7D%5Ctimes1.4%5Ctimes10%5E%7B-3%7D)
![V=8.4\times10^{3}\ V](https://tex.z-dn.net/?f=V%3D8.4%5Ctimes10%5E%7B3%7D%5C%20V)
Hence, The potential difference between the plates is ![8.4\times10^{3}\ V](https://tex.z-dn.net/?f=8.4%5Ctimes10%5E%7B3%7D%5C%20V)