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VLD [36.1K]
2 years ago
6

SOMONE PLEASE HELP ASAP!!!!

Physics
1 answer:
lidiya [134]2 years ago
3 0
It’s the blue color
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When two systems in contact are not at the same temperature, _____ occurs.expansionheat flowfrictionevaporation
Murljashka [212]

Heat flow occurs when two systems in contact are not at the same temperature.

What is heat flow?

  • when two bodies of different temperatures are in contact, heat flow takes place.
  • Heat flows till the two bodies in contact achieve equilibrium.
  • To achieve equilibrium, heat flows from hotter bodies to colder bodies.
  • There is no heat flow after achieving the state of equilibrium because the amount of heat flow from one body to the other is the same.

For more information, please visit: brainly.com/question/11297584?referrer=searchResults

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1 year ago
Stars give off a tremendous amount of thermal and ________ energy.(1 point) chemical chemical electrical electrical nuclear nucl
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I believe the answer is Nuclear energy
8 0
1 year ago
Two airplanes leave an airport at the same time. The velocity of the first airplane is 750 m/h at a heading of 51.3°. The veloci
abruzzese [7]
Refer to the diagram shown below.

In 2.4 hours, the distance traveled by the first airplane heading a 51.3° at 750 mph is 
a = 750*2.4 = 1800 miles.

The second airplane travels
b = 620*2.4 = 1488 mile

The angle between the two airplanes is
163° - 51.3° = 111.7°

Let c =  the distance between the two airplanes after 2.4 hours.
From the Law of Cosines, obtain
c² = a² + b² - 2ab cos(111.7°)
    = 3.24 x 10⁶ + 2.2141 x 10⁶
c = 2335.41 miles

Answer: 2335.4 miles

4 0
3 years ago
Read 2 more answers
A force on a particle depends on position such that F(x) = (3.00 N/m2)x2 + (6.00 N/m)x for a particle constrained to move along
Pachacha [2.7K]

Answer:

The work done by a particle from x = 0 to x = 2 m is 20 J.

Explanation:

A force on a particle depends on position constrained to move along the x-axis, is given by,

F(x)=(3\ N/m^2)x^2+(6\ N/m)x

We need to find the work done on a particle that moves from x = 0.00 m to x = 2.00 m.

We know that the work done by a particle is given by the formula as follows :

W=\int\limits {F{\cdot} dx}

W=\int\limits^2_0 {(3x^2+6x){\cdot} dx} \\\\W={(x^3}+3x^2)_0^2\\\\\W={(2^3}+3(2)^2)\\\\W=20\ J

So, the work done by a particle from x = 0 to x = 2 m is 20 J. Hence, this is the required solution.

3 0
3 years ago
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What is most likely to happen to light that hits an opaque object?
ddd [48]
B. is the answer.

C is not correct because the light is actually reflected off of an opaque object.
4 0
3 years ago
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