Answer:
The mentioned parental types are c+m- and c-m+. Thus, the recombinants will be c+m+ and c-m-.
Now, the given distance between c and m is 8 map units. Thus, the recombinant frequency is 8% or 0.08.
The total recombinants from 1000 plaques will come out to be 80,
Thus, the recombinants of each type will be 40.
Total parental type will be 920, and therefore, each parental type count will be 460.
Thus, expected c+m- = 460, expected c-m+ = 460, expected c+m+ = 40 and expected c-m- = 40.
the genetic material housed inside the cell nucleus is packaged in into these organized bundles.
- chromosomes
<span>If she has injuries on various parts of her body that are in different stages of healing.</span>
The answer is Have more allergies.
The type of nutrient intake that babies have in early development would affect the stability of gut<span> microbiomes that exist in their body.
Breastfeed babies tend to have more microbiomes that help them fight of foreign objects that come inside their system, and prevent allergies.</span>
<span>contractile vacuole
Contractile vacuoles are organelles that are responsible for excretion function. They perform osmoregulation which manages wastes, water and other needed materials in the cell. They are found in some prokaryoric organisms like the algae, protists, amoeba and other unicellular organisms.
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