Answer:
Yes, we can separate the liquids from solutions using distillation.
Explanation:
In distillation, the components or substances are separated from a liquid mixture by selective boiling and condensation. Distillation can result in substantially complete separation (near-pure components), or it can be a partial separation that increases the concentration of the selected components in the mixture. In both cases, the process takes advantage of the differences in the relative volatility of the components of the mix. In industrial chemistry, distillation is a unitary process of universal practical importance, but it is a process of physical separation, not a chemical reaction. Distillation is also be used to separate a solution from two or more liquids or fractions. They are called miscible liquids and must have different boiling points, e.g. B. ethanol and water or fermented fruit juice. A capacitor is used. A mixture is heated to just above 80 degrees Celsius (the boiling point of ethanol is 79 degrees Celsius). Ethanol evaporates and condenses. It can be collected in a cup. The water remains in the balloon.
There are three: Hydrogen, Nitrogen, and Oxygen.
Answer:
Ionic bonding is the complete transfer of valence electron(s) between atoms and is a type of chemical bond that generates two oppositely charged ions. By losing those electrons, these metals can achieve noble-gas configuration and satisfy the octet rule
Explanation:
Hope this helps
;)
You could first sift the sand out of the water with some sort of fine mesh that will catch the sand. Then, you can evaporate the water off of the salt, leaving crystallized salt, sand, and water vapor.
1) Balance of mass
CxHyOz + O2 ---> CO2 + H20
0.880 g + X = 1.760g + 0.720 g
=> X = 1.760g + 0.720g - 0.880g = 1.6 g of O2
2) C in CO2:
molar mass of CO2 = 44 g/mol
=> 12 g C / 44 g CO2 * 1.760 g CO2 = 0.480 g C
3) H in H2O
molar mass of H2O = 18.0 g/mol
2 g H / 18.0 g H2O * 0.720 g H2O = 0.080 g H
4) O
4a) O in CO2: 32gO / 44 g CO2 * 1.760 g CO2 = 1.280 g O
4b) O in H2O: 16gO / 18 gH2O * 0.720 g H2O = 0.640 g O
4c) O in CxHyOz = 1.280 g + 0.64 g - 1.6 g = 0.320 g O
5) Convert grams into moles
C: 0.480 g / 12 g/mol = 0.04 mol
H: 0.08 g / 1 g/mol = 0.08 mol
O: 0.32 g / 16 g/mol = 0.02 mol
6) Divide by the smallest number
C: 0.04 / 0.02 = 2
H: 0.08 / 0.02 = 4
O: 0.02 / 0.02 = 1
7) Use those numbers as subscripts for the empirical formula:
C2 H4 O
Answer: C2H4O