3./..........................................................
Moles of Ar = mass/atomic weight of Ar
= 22/39.948
= 0.55 moles
Hope this helps!
Answer:
70.34 litres
Explanation:
Using ideal gas law equation;
PV = nRT
Where;
P = pressure (atm)
V = volume (L)
n = number of moles (mol)
R = gas law constant (0.0821 Latm/molK)
T = temperature (K)
According to the information given in the question;
n = 3 moles
V = ?
P = 105.2 KPa = 105.2/101 = 1.04atm
T = 24.0°C = 24 + 273 = 297K
Using PV = nRT
1.04 × V = 3 × 0.0821 × 297
1.04V = 73.15
V = 73.15 ÷ 1.04
V = 70.34 litres.
Chemicals can enter the air, water, and soil when they are produced, used or disposed. Their impact on the environment is determined by the amount of the chemical that is released, the type and concentration of the chemical, and where it is found.
The empirical formula : C₁₂H₄F₇
The molecular formula : C₂₄H₈F₁₄
<h3>Further explanation</h3>
mol C (MW=12 g/mol)
mol H(MW=1 g/mol) :
mol F(MW=19 g/mol)
mol ratio of C : H : O =1.52 : 0.51 : 0.89=3 : 1 : 1.75=12 : 4 : 7
Empirical formula : C₁₂H₄F₇
(Empirical formula)n=molecular formula
( C₁₂H₄F₇)n=562 g/mol
(12.12+4.1+7.19)n=562
(281)n=562⇒ n =2
Molecular formula : C₂₄H₈F₁₄