Answer: The percent of yield is 50.03%.
Explanation:
First, we need to balance the equation:
⇒
We need to remember that the chemical equations are written in moles, so we have to convert the amounts in grams to moles, using the molecular weight of every compound: Al2O3 (101.96 g/mol), Al (29.98 g/mol) and O2 (31.99 g/mol).
In consequence, the amounts in moles of every compound will be:
Now, we have to find out which is the limit reagent or in other words, which of the reagents will be consumed first, taking into account the stoichiometric ratio of the balanced equation:
As you can see, the maximum amount (theoretically) of Al2O3 that can be produced is 0.1665 mol.
Finally, we have to use the yield formula to calculate the percent yield of the reaction:
Therefore, the percent of yield is 50.03%.
