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77julia77 [94]
3 years ago
5

How many orbitals surround the nucleus in a neutral atom of sulfur (S)? A. 1 B. 3 C. 9 D. 6

Chemistry
1 answer:
Igoryamba3 years ago
5 0

Answer:

it may be 3

Explanation:

i hope that..

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Electrons are the most<br> important electrons to an atom. a) outer b) inner
Gnom [1K]
The answer is A.Outer. Hope this helps
6 0
3 years ago
Which is one way that scientists ensure that data is reliable?
docker41 [41]

Answer:

letter b by replicating experiments

Explanation:

8 0
2 years ago
How many CaF are in a 1.7x10^25 please I need help fast!!
Gemiola [76]
<h3>Answer:</h3>

28 mol CaF

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 1.7 × 10²⁵ molecules CaF

[Solve] moles CaF

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                          \displaystyle 1.7 \cdot 10^{25} \ molecules \ CaF(\frac{1 \ mol \ CaF}{6.022 \cdot 10^{23} \ molecules \ CaF})
  2. [DA] Multiply/Divide [Cancel out units]:                                                         \displaystyle 28.2298 \ moles \ CaF

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

28.2298 mol CaF ≈ 28 mol CaF

7 0
3 years ago
Which soil particle is the smallest, drains water slowly, and holds too much water?
dsp73

Answer:

Clay

Explanation:

Since Clay has a very small particle size it compacts or has a high surface area which slows the path of water, holding it for longer periods compared to other soil components.

5 0
2 years ago
A 1.543 gram sample containing sulfate ion was treated with barium chloride reagent, and 0.2243 grams of barium sulfate was isol
Montano1993 [528]
Chemical reaction: SO₄²⁻ + Ba²⁺ → BaSO₄.
m(sample) = 1,543 g.
m(BaSO₄) = 0,2243 g.
n(BaSO₄) = m(BaSO₄) ÷ M(BaSO₄).
n(BaSO₄) = 0,2243 g ÷ 233,4 g/mol. 
n(BaSO₄) = 0,00096 mol.
n(BaSO₄) = n(SO₄²⁻).
ω(SO₄²⁻) = m(SO₄²⁻) ÷ m(sample).
ω(SO₄²⁻) = 0,00096 mol · 96 g/mol ÷ 1,543 g.
ω(SO₄²⁻) = 0,059 = 5,9%.
6 0
3 years ago
Read 2 more answers
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